anonymous
  • anonymous
Quick Question. I need help understanding steps to an example problem. Medal to most helpful.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
What is the resulting product of (x + (2 + 3i))^2?
anonymous
  • anonymous
kk. im here
anonymous
  • anonymous
Let me write it all out.

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More answers

anonymous
  • anonymous
x^2-4x+13
anonymous
  • anonymous
@Carpe_Diem77 @Spinex12
anonymous
  • anonymous
This is the example problem they gave me. I have to solve a problem similar to it, but I'm stuck because I don't know how they got the third number, 12, in the third step.
anonymous
  • anonymous
oh......... um.............. i messaged carpe to help she might be coming
anonymous
  • anonymous
Alright. thanks.
anonymous
  • anonymous
carpe, do u know?
anonymous
  • anonymous
ummmm no I would have to take some time to solve it but im a little busy....let @MathHelpPls help you
anonymous
  • anonymous
kk
anonymous
  • anonymous
what is ur guess so far
anonymous
  • anonymous
@StudyBuddy17
anonymous
  • anonymous
\[[x+(2+3i)]^{2}\] \[x^{2}+2[x \times(2+3i)]+(2+3i)^{2}\] \[x^{2}+2(2x+3x i)+(4+12i+9i)^{2}\] \[x^{2}+4x+6x i+4+12i-9\] \[x^{2}+4x+6x i+12i-5\]
anonymous
  • anonymous
I don't know where the 12i came from in the third step. I'm thinking...
anonymous
  • anonymous
@souleaterz
anonymous
  • anonymous
kk
anonymous
  • anonymous
@Hero @SolomonZelman @mathmale Could you help me?
mathmale
  • mathmale
\[[x+(2+3i)]^2\] is essentially the square of a binomial. What is \[(a+b)^2 ?\]
anonymous
  • anonymous
@dgcfhjmtyrfccvbcfgb should be banned
anonymous
  • anonymous
i read her other emails
anonymous
  • anonymous
\[(a + b)^{2} = a^{2} + 2ab + b^{2}\]
anonymous
  • anonymous
ummm....
anonymous
  • anonymous
idk
anonymous
  • anonymous
i couldnt figure it out
anonymous
  • anonymous
gtg bye
anonymous
  • anonymous
@mathmale
mathmale
  • mathmale
(a+b)^2=a^2+2ab+b^2 is correct. Thanks. Following this pattern, expand the following: (x + (2 + 3i))^2 (Treat x as you did 'a' and treat (+3i) as you did 'b.'
anonymous
  • anonymous
i just don't understand how they got 12i.
anonymous
  • anonymous
i understand all of the steps except when they inserted 12i in the third step.
mathmale
  • mathmale
Your \[x^{2}+2[x \times(2+3i)]+(2+3i)^{2}\]
mathmale
  • mathmale
is fine.
mathmale
  • mathmale
\[x^{2}+2[x \times(2+3i)]+(2+3i)^{2}\]
mathmale
  • mathmale
if you multiply out the middle term, you get 2x(2+3i), or 4x+6i. Agree or disagree?
anonymous
  • anonymous
wouldn't it be 4x + 6xi?
mathmale
  • mathmale
Note: the last term of your \[x^{2}+2(2x+3x i)+(4+12i+9i)^{2}\]
mathmale
  • mathmale
is incorrect because you have already squared (2+3i). Please note that the square of this binomial is 4 + 6i +9(-1 See whether this helps you to understand where that 12i comes from.
mathmale
  • mathmale
I'm sorry to be leaving in mid-stream, but have another commitment to take care of now. Good luck!
anonymous
  • anonymous
I think I got it. Thanks.

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