anonymous
  • anonymous
The figure below shows a rectangle ABCD having diagonals AC and DB: A rectangle ABCD is shown with diagonals AC and BD. Jimmy wrote the following proof to show that the diagonals of rectangle ABCD are congruent: Jimmy's proof: Statement 1: In triangle ADC and BCD, AD = BC (opposite sides of a rectangle are congruent) Statement 2: Angle ADC = Angle BCD (angles of a rectangle are 90°) Statement 3: Statement 4: Triangle ADC and BCD are congruent (by SAS postulate) Statement 5: AC = BD (by CPCTC)
Mathematics
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Which statement below completes Jimmy's proof? AB=AB (reflexive property of equality) AB=AB (transitive property of equality) DC=DC (reflexive property of equality) DC=DC (transitive property of equality)
anonymous
  • anonymous
anonymous
  • anonymous
@souleaterz @Anaise @callielovesyhuu @CallMeKiki @ganeshie8

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anonymous
  • anonymous
@celinegirl @Christian_10_ @Elsa213

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