Hope210
  • Hope210
will medal Solve 2x - 1 < 7 and 5x + 3 < 3. {x | x < 0} {x | x < 4} {x | 0 < x < 4}
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Landon34
  • Landon34
@Hope210
Hope210
  • Hope210
okay
Landon34
  • Landon34
Im gonna write this down in my notebook, and Ill try to solve it.

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Hope210
  • Hope210
cool thanks
Landon34
  • Landon34
It will be a minute or 2.
Landon34
  • Landon34
you can go do something else while I solve this.
Hope210
  • Hope210
okay bye
Landon34
  • Landon34
@whpalmer4
Landon34
  • Landon34
k im bak
Landon34
  • Landon34
I would recommend you check out https://www.khanacademy.org/
Landon34
  • Landon34
im gonna do something else, bye.
whpalmer4
  • whpalmer4
Solve \(2x - 1 < 7\) and \(5x + 3 < 3\) Start with \[2x-1<7\]We want to get \(x\) alone on one side of the inequality sign with everything else on the other. You can do anything you want as long as you do it to both sides. However, if you multiply or divide by a negative number, you must change the direction of the inequality sign. \[2x-1 < 7\]Let's add \(1\) to both sides:\[2x-1+1 < 7 + 1\]\[2x < 8\]Now let's divide both sides by \(2\):\[\frac{2x}{2} < \frac{8}{2}\]\[x<4\] We have determined that our solution is only going to contain values which meet the constraint that \(x<4\). We don't know yet if it means that ALL values of \(x<4\) work. For that, you need to repeat the process on the other inequality, and then look at the combination.
Hope210
  • Hope210
Thank you
whpalmer4
  • whpalmer4
@Hope210 what did you get for your final answer?

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