Ray1998
  • Ray1998
Please help! Will give medal and fan. Thank you in advance :) 1. Simplify the expression. -5 + i/2i
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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ybarrap
  • ybarrap
1/i = -i So i/2i = i/2 * -i = \(\cfrac{-i^2}{2}\) See that? Then -5 + i/2i = \(-5+\cfrac{-i^2}{2}\) Then \(i^2=-1\) Can you finish it?
Ray1998
  • Ray1998
Okay. Thank you. I don't think I can honestly, I'm not at all familiar with these problems. I'm very behind in my Algebra class. I don't expect you to give me the answer, but if you could just work with me on it :) that would be great. @ybarrap
ybarrap
  • ybarrap
You have $$ -5 +\cfrac{i}{2i} $$ Right?

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Ray1998
  • Ray1998
Right
ybarrap
  • ybarrap
I explained that 1/i = -i, which you can use; however you can also cancel the i's: $$ -5 +\cfrac{\cancel i}{2\cancel i}=-5+\cfrac{1}{2} $$ See that?
ybarrap
  • ybarrap
This is the easier approach; however, the 1st approach shows how things work if you play with the imaginary number, i. BTW, \(i=\sqrt{-1}\) so \(i^2=-1\), just in case
ybarrap
  • ybarrap
does any of this make any sense?
Ray1998
  • Ray1998
Okay. So it's easiest to keep the i's in the equation?
Ray1998
  • Ray1998
Em, I'm trying to grasp it all lol.
ybarrap
  • ybarrap
yes, if you cancel them, you can just deal with them like regular old numbers
ybarrap
  • ybarrap
keep trying, it's fulfilling and exciting
Ray1998
  • Ray1998
Okay. Lol I'm not so sure about it being exciting, so much as complicated.
ybarrap
  • ybarrap
did I say that, lol
Ray1998
  • Ray1998
Yes lol
ybarrap
  • ybarrap
There was a time when people thought that you could not take a square root of a negative number, then someone decided, not that complicated, just make it the letter "i" and deal with it like an ordinary number and see what happens.
Ray1998
  • Ray1998
Okay.
ybarrap
  • ybarrap
So once you've simplified you have $$ -5 + \cfrac{1}{2}=-4\cfrac{1}{2}=-\cfrac{9}{2} $$
Ray1998
  • Ray1998
Alright
ybarrap
  • ybarrap
good luck \(:-) \)
Ray1998
  • Ray1998
Thank you @ybarrap
ybarrap
  • ybarrap
You're welcome

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