anonymous
  • anonymous
Oil is delivered to a refinery between the hours of midnight (t = 0) and 5 a.m. (t = 5). Selected values of the rate of delivery are shown in the table below, with t measured in hours past midnight, and R(t) measured in gallons per hour. Use 4 trapezoids to estimate the total amount of oil to the nearest gallon that is delivered between midnight and 5 a.m.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@terenzreignz @jim_thompson5910 @zepdrix This is fairly easy just want to confirm my answer. I got 1075
jim_thompson5910
  • jim_thompson5910
you forgot to post the table
anonymous
  • anonymous
https://gyazo.com/9252eae33a7f37da2771d882787b4a8c

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anonymous
  • anonymous
My apologies
jim_thompson5910
  • jim_thompson5910
that's ok
anonymous
  • anonymous
Lol
anonymous
  • anonymous
I was reading another problem, my bad
jim_thompson5910
  • jim_thompson5910
I'm hitting a stumbling block. It seems like the "4 trapezoids" should be "5 trapezoids" 4 doesn't work because you have the right edges that don't land on given table values
jim_thompson5910
  • jim_thompson5910
I guess we could leave off the last column of the table since the 5 am cut off happens there
anonymous
  • anonymous
What? I was able to do it with 4 no problem unless you see something I don't
jim_thompson5910
  • jim_thompson5910
oh nvm, I mistakenly put 3 in there
jim_thompson5910
  • jim_thompson5910
I'm getting something larger than 1075
anonymous
  • anonymous
Hmm
anonymous
  • anonymous
I'll write out what U did.
anonymous
  • anonymous
I*
jim_thompson5910
  • jim_thompson5910
here is what the trapezoids look like
1 Attachment
anonymous
  • anonymous
\[(\frac{ 100+250 }{ 2 })+(\frac{ 250+200 }{ 2 })+( 200+350)+(\frac{ 350+100 }{ 2 } )\]
jim_thompson5910
  • jim_thompson5910
yep and that leads to the answer I'm getting, which is 1175
anonymous
  • anonymous
Probably miscalculated. Let me give it another go
anonymous
  • anonymous
You are right.

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