Ray1998
  • Ray1998
Last question, I promise. What is the solution of the linear quadratic system of equations? y = x^2 + 5x - 3 y - x = 2 I need to be walked through it, not just given the answer. Will give fan and medal. Thank you in advance! :)
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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Ray1998
  • Ray1998
Do you plug the 2 in like this? y = 2^2 + 5(2) - 3
ybarrap
  • ybarrap
Not exactly... check this out: So you have $$ y-x=2\\ y=2+x\\ $$ Plug in to your quadratic $$ y=x^2+5x-3=2+x\\ x^2+5x-x-3-2=0\\ x^2+4x-5=0\\ (x-1)(x+5)=0 $$ So there are two solutions if x=1 the equation is true if x=-5 the equation is true We know that y=2+x So when x=1, y =3 and when x=-5, y = -3 Two solutions: $$ (1,3)\text{ and }(-5,-3) $$ Make sense?
Ray1998
  • Ray1998
Sorta. I'll have to look at it some more, but I get part of it. Thank you. :)

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ybarrap
  • ybarrap
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Ray1998
  • Ray1998
Right. I understand that. :)
ybarrap
  • ybarrap
That's the hard part - the math is the easier part.
Ray1998
  • Ray1998
Oh xD I meant that I understood the wording. "A solution is when one equation intersects with another." Yeh, the graphing is a whole other ball game for me lol. Thank you for helping me though :) @ybarrap I sincerely apologize for my slowness. I kept hoping someone else would help out so you wouldn't have to keep working with me lol xD
ybarrap
  • ybarrap
Not a big deal. If I can get you interested even a little bit in math, I would be happy. In other words, you're welcome.

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