anonymous
  • anonymous
divide: (x^2-6x-7)/(3x^2-147) divided by (x^2+8x+7)/(x^2+14x+49) here's what i have so far-- (x^2-6x-7)/(3x^2-147) * (x^2+14x+49)/(x^2+8x+7) i factored it out-- (x+1)(x-7)/3x^2-147 * (x+7)(x+7)/(x+1)(x+7) what im getting stuck on is the 3x^2-147. I know i have to get it to 3(x^2-27), but i cant factor it further after that, right? and my online homework program wont accept it as just 3(x^2-27). I tried to find factors of 27 but it's only 1, 3, 9 and 27. Am I missing something completely obvious? I'm at a loss here.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
you sure it is a square and not a cube?
anonymous
  • anonymous
\[x^3-27\] factors because it is the difference of two cubes just asking, maybe it is not
anonymous
  • anonymous
it's definitely a square
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anonymous
  • anonymous
yes, so it is
anonymous
  • anonymous
hmm apparently the correct answer is \(\frac{1}{3}\) so lets see how we can get that ...
anonymous
  • anonymous
lol
anonymous
  • anonymous
oh gosh okay
anonymous
  • anonymous
it is not \[3x^2-147=3(x^2-27)\] it is \[3x^2-147=3(x^2-49)\]
anonymous
  • anonymous
arithmetic will screw you up every time you good from there?
anonymous
  • anonymous
.. yes omg,, of course it was a simple mistake wow thank you for your help

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