Lord2clash
  • Lord2clash
Can i get help with Area and Perimeters of Polygons?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Lord2clash
  • Lord2clash
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Lord2clash
  • Lord2clash
@the_ocean_girl can you help with this?
the_ocean_girl
  • the_ocean_girl
Ouch sorry Clash. Not in that part of geometry yet!

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Lord2clash
  • Lord2clash
okay cx thanks anyways cx
anonymous
  • anonymous
So what work have you gotten done on it so far?
Lord2clash
  • Lord2clash
the area of the unshaded section is 320 and thats it...
anonymous
  • anonymous
And do you have any clue how you'd find the shaded area?
Lord2clash
  • Lord2clash
not exactly i saw the formula (i think) somewhere but i cant find it now...
anonymous
  • anonymous
Well to find the shaded area we would do \[\large \sf Area~of~hexagon~-~Area~of~unshaded~region~=~Area~of~shaded~area\] Since we have the area of the unshaded region, what we need to find now is the area of the hexagon. Do you know how to do that?
Lord2clash
  • Lord2clash
Honestly no. i didn't read the section on it.... but im willing to learn how cx
anonymous
  • anonymous
Probably the easiest way is \[\large \sf Area= \frac{1}{2} \times perimeter \times apothem\] but you can only use this way if you have the apothem.
Lord2clash
  • Lord2clash
witch i do cx
Lord2clash
  • Lord2clash
apothem = 17.32
Lord2clash
  • Lord2clash
so 1/2(20*6)17.32
anonymous
  • anonymous
Yup
Lord2clash
  • Lord2clash
1039.2?
Lord2clash
  • Lord2clash
so A?
anonymous
  • anonymous
Yup. Now subtract the area of the unshaded region to get your answer.
Lord2clash
  • Lord2clash
710 B
anonymous
  • anonymous
Correct
Lord2clash
  • Lord2clash
thanks cx
anonymous
  • anonymous
No problem

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