anonymous
  • anonymous
Perform the indicated operations.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
anyone?
anonymous
  • anonymous
@pooja195

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anonymous
  • anonymous
First get common denominator.
anonymous
  • anonymous
20?
anonymous
  • anonymous
Yeap, thats a great way to start.
anonymous
  • anonymous
ok now what?
anonymous
  • anonymous
Combine it into a single fraction.
anonymous
  • anonymous
a+2+a-1+a-3?
anonymous
  • anonymous
You got: \[\frac{a+2}{4b}-\frac{a-1}{10b}+\frac{a-3}{5b}\]\[=\frac{5(a+2)}{20b}-\frac{2(a-1)}{20b}+\frac{4(a-3)}{20b}\]
anonymous
  • anonymous
ok
anonymous
  • anonymous
Now we have the same denominator. Now we want to get them into a single fraction. So we get: \[\frac{5(a+2)-2(a-1)+4(a-3)}{20b}\]
anonymous
  • anonymous
Now the next step would be to simplify the nominator.
anonymous
  • anonymous
5a+10-2A+2+4A-12
anonymous
  • anonymous
Correct
anonymous
  • anonymous
Try so simplify it further
anonymous
  • anonymous
7A
anonymous
  • anonymous
Yes, so the final answer is \[\frac{7a}{20b}\]
anonymous
  • anonymous
7A/20B?
anonymous
  • anonymous
Yea! good job :)
anonymous
  • anonymous
THANKS I HAVE ONE MORE QUESTION
anonymous
  • anonymous
sure
anonymous
  • anonymous
Solve the inequality.
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
these are ones i don't understand
anonymous
  • anonymous
Okay, lets get common denominator first.
anonymous
  • anonymous
6
anonymous
  • anonymous
Yeap, so we get\[\frac{2x}{6}+\frac{3(1-x)}{6}\ge1\]
anonymous
  • anonymous
Lets put it into a single fraction.
anonymous
  • anonymous
\[\frac{2x+3(1-x)}{6}\ge1\]
anonymous
  • anonymous
Try and simplify the nominator

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