Azionne
  • Azionne
2x - 1 ≤ x + 5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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just_one_last_goodbye
  • just_one_last_goodbye
If this helps please give me a medal ^_^
Azionne
  • Azionne
why do u always post that help me learn this.
just_one_last_goodbye
  • just_one_last_goodbye
I post it to help you as soon as possible ._.

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More answers

just_one_last_goodbye
  • just_one_last_goodbye
Do you really want to learn?
Azionne
  • Azionne
yes i do want to learn
just_one_last_goodbye
  • just_one_last_goodbye
Add 1 to both sides.
Azionne
  • Azionne
ok did that
just_one_last_goodbye
  • just_one_last_goodbye
\[2x - 1 + 1 \le x + 5 + 1\]
Azionne
  • Azionne
ok help me continue to do this
just_one_last_goodbye
  • just_one_last_goodbye
The ones on the left cancel out ^_^
just_one_last_goodbye
  • just_one_last_goodbye
5 + 1 = 6
just_one_last_goodbye
  • just_one_last_goodbye
IT should look like this now \[2x \le x + 6\]
Azionne
  • Azionne
thats it?
just_one_last_goodbye
  • just_one_last_goodbye
Nope ^_^ last step
Azionne
  • Azionne
ok...
just_one_last_goodbye
  • just_one_last_goodbye
We subtract x from both sides now :D
Azionne
  • Azionne
Ugh ok how do i do that step?
just_one_last_goodbye
  • just_one_last_goodbye
\[2x - x \le x + 6 - x\]
Azionne
  • Azionne
what do u get so i can check my work?
just_one_last_goodbye
  • just_one_last_goodbye
I get \[x \le 6\]
Azionne
  • Azionne
idk if i am being tricked but thats what i got
just_one_last_goodbye
  • just_one_last_goodbye
Nope thats the answer ^_^
Tsukiyama_Shuu
  • Tsukiyama_Shuu
Thats right :)
just_one_last_goodbye
  • just_one_last_goodbye
I doubled checked with my calculator
Tsukiyama_Shuu
  • Tsukiyama_Shuu
i did that in my head
Tsukiyama_Shuu
  • Tsukiyama_Shuu
But its right xD

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