anonymous
  • anonymous
Find the area and the circumference of a circle with diameter 6 ft. Use the value 3.14 for pi, and do not round your answers.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jim_thompson5910
  • jim_thompson5910
You'll use these formulas A = pi*r^2 C = pi*d A = area C = circumference r = radius (half of the diameter) d = diameter pi = 3.14 approximately
jim_thompson5910
  • jim_thompson5910
keep in mind that r^2 is not the same as r*2
anonymous
  • anonymous
So for the circumference, 3.14*6?

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More answers

anonymous
  • anonymous
Is the area 9ft^2 ?
jim_thompson5910
  • jim_thompson5910
area would be 9*pi = 9*3.14 = ??
anonymous
  • anonymous
28.26?
jim_thompson5910
  • jim_thompson5910
yep that's the area
anonymous
  • anonymous
18.84 is the circumference?
mathmale
  • mathmale
@Snufflebug02: Please be sure to include the correct units of measurement with your answers. 18.84 should not be left standing alone. Neither should 28.26.
anonymous
  • anonymous
18.84 ft^2 and 28.26 ft^2
anonymous
  • anonymous
Is that correct?
jim_thompson5910
  • jim_thompson5910
`18.84 ft^2` is partially correct the 18.84 is correct, but the units for circumference are going to be ft instead of ft^2
anonymous
  • anonymous
Okay thank you! I have another question, if you have time :)
jim_thompson5910
  • jim_thompson5910
imagine you cut the circle and stretched it out to form a line like you see in this animation https://upload.wikimedia.org/wikipedia/commons/6/67/2pi-unrolled.gif
anonymous
  • anonymous
A rectangle is placed around a semicircle as shown below. The width of the rectangle is 9 cm. Find the area of the shaded region. Use the value 3.14 for pi, and do not round your answer. Be sure to include the correct unit in your answer.
anonymous
  • anonymous
Yes I understand now. Thank you for talking me through it
jim_thompson5910
  • jim_thompson5910
`A rectangle is placed around a semicircle as shown below` you forgot to post the image
anonymous
  • anonymous
I tried. I'm not sure how too
jim_thompson5910
  • jim_thompson5910
click the "attach file" button or host the image on a site like imgur then post the link
anonymous
  • anonymous
I don't see an "attach file" button. how do i use imgur?
jim_thompson5910
  • jim_thompson5910
you go to http://imgur.com/ then drag and drop your image to upload it then share the link here
anonymous
  • anonymous
It's not letting me. I'll try to explain it. Its a rectangle with a semicircle inside of it. And the top right and left corners are shaded in. That is the area that we need to find
anonymous
  • anonymous
I'm sorry if this is difficult
jim_thompson5910
  • jim_thompson5910
like this? |dw:1449876974334:dw|
anonymous
  • anonymous
Yes!
anonymous
  • anonymous
The width is 9 cm
jim_thompson5910
  • jim_thompson5910
I'm assuming this rectangle is really a square?
anonymous
  • anonymous
I don't think so. I mean the question stipulates that it is a rectangle
jim_thompson5910
  • jim_thompson5910
how is the figure labeled? draw on my drawing (click the pencil of my drawing)
anonymous
  • anonymous
Okay one sec
anonymous
  • anonymous
|dw:1449877590791:dw|
anonymous
  • anonymous
That is all that it provides. It literally looks just like what you drew
jim_thompson5910
  • jim_thompson5910
ok I'm going to assume it's a square. It doesn't work any other way if it's a square, then the bottom portion is also 9 |dw:1449877730066:dw|
jim_thompson5910
  • jim_thompson5910
how is it shaded?
anonymous
  • anonymous
|dw:1449877790350:dw| Like the \
jim_thompson5910
  • jim_thompson5910
ok
jim_thompson5910
  • jim_thompson5910
what is the area of the square (ignore the semicircle inside)
anonymous
  • anonymous
Liek this Area of a qaaqs Area of square a= a^2 right?
jim_thompson5910
  • jim_thompson5910
yeah so 9*9 = ???
anonymous
  • anonymous
My keyboard is acting up, disregard the jumble words
jim_thompson5910
  • jim_thompson5910
its fine
anonymous
  • anonymous
yes so 81
jim_thompson5910
  • jim_thompson5910
now onto the area of the semicircle |dw:1449878066751:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1449878083046:dw|
jim_thompson5910
  • jim_thompson5910
area of semicircle = (area of full circle)/2 area of full circle = pi*r^2
anonymous
  • anonymous
20.25 is the area?
jim_thompson5910
  • jim_thompson5910
r = 4.5 r^2 = 4.5^2 = 20.25
jim_thompson5910
  • jim_thompson5910
you forgot about multiplying by pi = 3.14 and then dividing that result by 2
anonymous
  • anonymous
so 31.79 is the answer
jim_thompson5910
  • jim_thompson5910
I'm getting 31.7925
anonymous
  • anonymous
that's the area of the shaded region?
jim_thompson5910
  • jim_thompson5910
area of square = 81 area of semi-circle = 31.7925 area of shaded region = (area of square) - (area of semi circle)
anonymous
  • anonymous
So 49.20?
jim_thompson5910
  • jim_thompson5910
area of square = 81 area of semi-circle = 31.7925 area of shaded region = (area of square) - (area of semi circle) area of shaded region = 81 - 31.7925 area of shaded region = 49.2075
anonymous
  • anonymous
Would you right =write* the whole 49.20752 as your answer . with out the two lol. idk on this site my keyboard is really werid
jim_thompson5910
  • jim_thompson5910
I'd stick with 49.2075
anonymous
  • anonymous
Ok thanks lol
jim_thompson5910
  • jim_thompson5910
no problem

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