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You'll use these formulas A = pi*r^2 C = pi*d A = area C = circumference r = radius (half of the diameter) d = diameter pi = 3.14 approximately
keep in mind that r^2 is not the same as r*2
So for the circumference, 3.14*6?
Is the area 9ft^2 ?
area would be 9*pi = 9*3.14 = ??
yep that's the area
18.84 is the circumference?
@Snufflebug02: Please be sure to include the correct units of measurement with your answers. 18.84 should not be left standing alone. Neither should 28.26.
18.84 ft^2 and 28.26 ft^2
Is that correct?
`18.84 ft^2` is partially correct the 18.84 is correct, but the units for circumference are going to be ft instead of ft^2
Okay thank you! I have another question, if you have time :)
imagine you cut the circle and stretched it out to form a line like you see in this animation https://upload.wikimedia.org/wikipedia/commons/6/67/2pi-unrolled.gif
A rectangle is placed around a semicircle as shown below. The width of the rectangle is 9 cm. Find the area of the shaded region. Use the value 3.14 for pi, and do not round your answer. Be sure to include the correct unit in your answer.
Yes I understand now. Thank you for talking me through it
`A rectangle is placed around a semicircle as shown below` you forgot to post the image
I tried. I'm not sure how too
click the "attach file" button or host the image on a site like imgur then post the link
I don't see an "attach file" button. how do i use imgur?
you go to http://imgur.com/ then drag and drop your image to upload it then share the link here
It's not letting me. I'll try to explain it. Its a rectangle with a semicircle inside of it. And the top right and left corners are shaded in. That is the area that we need to find
I'm sorry if this is difficult
like this? |dw:1449876974334:dw|
The width is 9 cm
I'm assuming this rectangle is really a square?
I don't think so. I mean the question stipulates that it is a rectangle
how is the figure labeled? draw on my drawing (click the pencil of my drawing)
Okay one sec
That is all that it provides. It literally looks just like what you drew
ok I'm going to assume it's a square. It doesn't work any other way if it's a square, then the bottom portion is also 9 |dw:1449877730066:dw|
how is it shaded?
|dw:1449877790350:dw| Like the \
what is the area of the square (ignore the semicircle inside)
Liek this Area of a qaaqs Area of square a= a^2 right?
yeah so 9*9 = ???
My keyboard is acting up, disregard the jumble words
yes so 81
now onto the area of the semicircle |dw:1449878066751:dw|
area of semicircle = (area of full circle)/2 area of full circle = pi*r^2
20.25 is the area?
r = 4.5 r^2 = 4.5^2 = 20.25
you forgot about multiplying by pi = 3.14 and then dividing that result by 2
so 31.79 is the answer
I'm getting 31.7925
that's the area of the shaded region?
area of square = 81 area of semi-circle = 31.7925 area of shaded region = (area of square) - (area of semi circle)
area of square = 81 area of semi-circle = 31.7925 area of shaded region = (area of square) - (area of semi circle) area of shaded region = 81 - 31.7925 area of shaded region = 49.2075
Would you right =write* the whole 49.20752 as your answer . with out the two lol. idk on this site my keyboard is really werid
I'd stick with 49.2075
Ok thanks lol