Find the area and the circumference of a circle with diameter 6 ft. Use the value 3.14 for pi, and do not round your answers.

- anonymous

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- jim_thompson5910

You'll use these formulas
A = pi*r^2
C = pi*d
A = area
C = circumference
r = radius (half of the diameter)
d = diameter
pi = 3.14 approximately

- jim_thompson5910

keep in mind that r^2 is not the same as r*2

- anonymous

So for the circumference, 3.14*6?

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## More answers

- anonymous

Is the area 9ft^2 ?

- jim_thompson5910

area would be 9*pi = 9*3.14 = ??

- anonymous

28.26?

- jim_thompson5910

yep that's the area

- anonymous

18.84 is the circumference?

- mathmale

@Snufflebug02: Please be sure to include the correct units of measurement with your answers. 18.84 should not be left standing alone. Neither should 28.26.

- anonymous

18.84 ft^2 and 28.26 ft^2

- anonymous

Is that correct?

- jim_thompson5910

`18.84 ft^2` is partially correct
the 18.84 is correct, but the units for circumference are going to be ft instead of ft^2

- anonymous

Okay thank you! I have another question, if you have time :)

- jim_thompson5910

imagine you cut the circle and stretched it out to form a line
like you see in this animation
https://upload.wikimedia.org/wikipedia/commons/6/67/2pi-unrolled.gif

- anonymous

A rectangle is placed around a semicircle as shown below. The width of the rectangle is 9 cm. Find the area of the shaded region. Use the value 3.14 for pi, and do not round your answer. Be sure to include the correct unit in your answer.

- anonymous

Yes I understand now. Thank you for talking me through it

- jim_thompson5910

`A rectangle is placed around a semicircle as shown below`
you forgot to post the image

- anonymous

I tried. I'm not sure how too

- jim_thompson5910

click the "attach file" button
or host the image on a site like imgur then post the link

- anonymous

I don't see an "attach file" button.
how do i use imgur?

- jim_thompson5910

you go to
http://imgur.com/
then drag and drop your image to upload it
then share the link here

- anonymous

It's not letting me. I'll try to explain it. Its a rectangle with a semicircle inside of it. And the top right and left corners are shaded in. That is the area that we need to find

- anonymous

I'm sorry if this is difficult

- jim_thompson5910

like this?
|dw:1449876974334:dw|

- anonymous

Yes!

- anonymous

The width is 9 cm

- jim_thompson5910

I'm assuming this rectangle is really a square?

- anonymous

I don't think so. I mean the question stipulates that it is a rectangle

- jim_thompson5910

how is the figure labeled? draw on my drawing (click the pencil of my drawing)

- anonymous

Okay one sec

- anonymous

|dw:1449877590791:dw|

- anonymous

That is all that it provides. It literally looks just like what you drew

- jim_thompson5910

ok I'm going to assume it's a square. It doesn't work any other way
if it's a square, then the bottom portion is also 9
|dw:1449877730066:dw|

- jim_thompson5910

how is it shaded?

- anonymous

|dw:1449877790350:dw|
Like the \

- jim_thompson5910

ok

- jim_thompson5910

what is the area of the square (ignore the semicircle inside)

- anonymous

Liek this
Area of a qaaqs
Area of square a= a^2 right?

- jim_thompson5910

yeah so 9*9 = ???

- anonymous

My keyboard is acting up, disregard the jumble words

- jim_thompson5910

its fine

- anonymous

yes so 81

- jim_thompson5910

now onto the area of the semicircle
|dw:1449878066751:dw|

- jim_thompson5910

|dw:1449878083046:dw|

- jim_thompson5910

area of semicircle = (area of full circle)/2
area of full circle = pi*r^2

- anonymous

20.25 is the area?

- jim_thompson5910

r = 4.5
r^2 = 4.5^2 = 20.25

- jim_thompson5910

you forgot about multiplying by pi = 3.14
and then dividing that result by 2

- anonymous

so 31.79 is the answer

- jim_thompson5910

I'm getting 31.7925

- anonymous

that's the area of the shaded region?

- jim_thompson5910

area of square = 81
area of semi-circle = 31.7925
area of shaded region = (area of square) - (area of semi circle)

- anonymous

So 49.20?

- jim_thompson5910

area of square = 81
area of semi-circle = 31.7925
area of shaded region = (area of square) - (area of semi circle)
area of shaded region = 81 - 31.7925
area of shaded region = 49.2075

- anonymous

Would you right =write* the whole 49.20752 as your answer . with out the two lol. idk on this site my keyboard is really werid

- jim_thompson5910

I'd stick with 49.2075

- anonymous

Ok thanks lol

- jim_thompson5910

no problem

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