Gokuporter
  • Gokuporter
If the ratio of the two rectangles remains 4 to 5, is it possible for the area of the smaller rectangle to be 8 square feet and the area of the larger rectangle to be 15 square feet? Explain why or why not.
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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Gokuporter
  • Gokuporter
@Directrix
welshfella
  • welshfella
if the ratio of corresponding sides is 4:5 then the ratio of their areas is 4^2 : 5^2 - that is 16:25
welshfella
  • welshfella
so if the area of smaller one is 8 we have 8/x = 16/25 where x is the area of the larger rectangle

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welshfella
  • welshfella
if you solve that for x you'll se that its not 15
welshfella
  • welshfella
did you follow that process?
Gokuporter
  • Gokuporter
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Gokuporter
  • Gokuporter
yeah
welshfella
  • welshfella
yes thats it
welshfella
  • welshfella
So its not possible for the rectangle to have an area of 15 .

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