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what does it mean for a matrix to be singular?
and for that matter, what does A and B have to do with B^* being singular?
a matrix is singular iff its determinant =0
and im not sure
it was 2 parts of the question part A was to find AB part A was this part
right, so we need the determinant of the 3x3 to be 0 ... how far have you gotten?
.... by working the determinant process id imagine. of course, for a 3x3 i do the shortcut process similar to a 2x2
i only know to do the 2x2 so far
the shortcut on a 3x3 is to copy the first 2 columns onto the end, and multiply the diagonals
write down the values of ab and c ... where do abc come from?
idk that what the question ask
you say this question is part of another one?
thats the whole question
and you sure that when you drew it up ... you made the correct entries? with pq and r?
yep thats exactly whats there
well im out of ideas on how to make this sensible then lol.
i can make an equation of a plane with pqr as variables ... but ive got no idea how that helps in finding some rather ambiguous abc values.
have you worked the determinant?
and when we set that equal to 0 we get an infinite number of solutions .... all the points in a plane. are they wanting the solution set, or something more concrete?
(a,b,c) = (3,3,-1) is a solution, since that makes the last column the same as the first (a,b,c) = (0,2,2) is a solution, since that makes the last column the same as the second and any linear combination of the first 2 columns would be a solution as well
6x +0y = 2a 6x+4y = 2b -2x+4y = 2c
can it = to 0,0,0 also?
yes it can :) let x=0 and y=0