LifeIsADangerousGame
  • LifeIsADangerousGame
Can someone help me with these last three calculus problems? I'm working on finding the volume of a solid that is formed by revolving the region by the x or y axis.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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tkhunny
  • tkhunny
Please put enough information in the VERY FIRST post. This includes your best efforts at a solution. Many people see nothign in the first post and never come back.
LifeIsADangerousGame
  • LifeIsADangerousGame
LifeIsADangerousGame
  • LifeIsADangerousGame
@tkhunny Sorry, I'll edit it

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Arihangdu
  • Arihangdu
Uh no questions how to solve?
Arihangdu
  • Arihangdu
Uh no questions how to solve?
tkhunny
  • tkhunny
Sorry, disconnected... Why are you struggling with this? What have you tried? \(\pi r^{2}h\) -- The area of a circle. Differential with respect to h, \(\pi r^2\;dh\) Add them all up. \(\int\limits_{0}^{4} \pi r^{2}\;dh = \int\limits_{0}^{4} \pi (\sqrt{x})^{2}\;dx\)
LifeIsADangerousGame
  • LifeIsADangerousGame
Oh I see. I went about it the wrong way, I had tried it in the same way you would for finding the area underneath a curve.
tkhunny
  • tkhunny
It's about the same.
tkhunny
  • tkhunny
Second one is nearly identical. Set it up!
LifeIsADangerousGame
  • LifeIsADangerousGame
After I do (sqrtx)^2 dx, and I get just x dx, do I get the anti derivative and go from there?
tkhunny
  • tkhunny
It's an integral. How else do you plan to evaluate it? Go! You already know how to proceed. No more hesitating.
tkhunny
  • tkhunny
Third one is ALMOST the same. Just subtract the missing piece next to the y-axis. \(\pi 1^{2} 4 = 4\pi\). You'll be done in no time.
LifeIsADangerousGame
  • LifeIsADangerousGame
8pi for the first one?
tkhunny
  • tkhunny
Not a clue. I didn't work the problem. Are you confident?
LifeIsADangerousGame
  • LifeIsADangerousGame
Not in the least
LifeIsADangerousGame
  • LifeIsADangerousGame
But I guess it don't really mind by now, I just want to finish everything
tkhunny
  • tkhunny
Not good enough. If you do nothing incorrectly on purpose, why would it not be correct?
LifeIsADangerousGame
  • LifeIsADangerousGame
That's true. It should be correct then
Arihangdu
  • Arihangdu
👍🏻 job is done.

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