anonymous
  • anonymous
How can i solve linear equations in one variable?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
zepdrix
  • zepdrix
These types of equations?\[\large\rm 4x+3=2x-1\]
anonymous
  • anonymous
yes
zepdrix
  • zepdrix
Do you remember the PEMDAS acronym? :) It tells you how to prioritize these different operations when trying to simplify something like this:\[\large\rm 5+6(2-1)\div2\]You prioritize brackets highest, doing the 2-1 first.\[\large\rm 5+6(1)\div2\]Then multiplying the 6 and 1,\[\large\rm 5+6(1)\div2\]Then division,\[\large\rm 5+3\]and finally adding,\[\large\rm 8\] You might wonder how that applies to algebraic equations involving one variable. Well, it turns out that `usually`, when you're trying to solve for some unknown, you would like to perform these steps in reverse. That is usually the most straight forward approach.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ooh
zepdrix
  • zepdrix
Lemme set up a more straight forward example actually,\[\large\rm 4x-3=9\]The idea is, in order to get x alone, solving for it, you need to "undo" a bunch of operations. So in this example, notice that the x is being `multiplied by 4` and `subtracted by 3`. We want to think of this PEMDAS idea but in reverse, we would like "undo" the most simple steps first. So to undo subtraction, we use addition. We'll start by adding 3 to each side of the equation. (By making the same change to each side, the equation stays true and balanced).\[\large\rm 4x-3+3=9+3\]The subtraction and addition undo one another on the left side of the equation,\[\large\rm 4x=9+3\]
zepdrix
  • zepdrix
I know I'm rambling on a bit here :) lol but it's a fun question
anonymous
  • anonymous
im confuse because the question
zepdrix
  • zepdrix
the question? :o
anonymous
  • anonymous
ya this is for my school work and i do not understand at all.the way she wrote the question
zepdrix
  • zepdrix
She gave you this question: `How can i solve linear equations in one variable?` and wants you to explain?
anonymous
  • anonymous
yes
anonymous
  • anonymous
also KEEP IT ___________________. The goal is to figure out how much each x weight weighs. You do this by getting one x on one side and its value on the other side. STEPS TO SOLVING AN EQUATION 1. Simplify each side of the __________________. 2. Get the __________________ on one side of the ___________________. 3. Get the _____________ by ___________________. (Solve for the variable) 4. ___________ your solution. Follow along on page 3, Example 1. E2(x + 1) = 5x + 4 E x Simplify each side of the equation.
zepdrix
  • zepdrix
1. Simplify each side of the `equation`. Example: (Not using your example cause I'm not sure what the E's are about)\[\large\rm 2(x+3)=5x+1\]Simplifying the left side gives us,\[\large\rm 2x+6=5x+1\]
zepdrix
  • zepdrix
2. Get the `variable` on one side of the `equation`. We would like all of the x's on one side of the equation. It's usually better to move the smaller x's around. So in this example, I'll subtract 2x,\[\large\rm 6=5x+1-2x\]\[\large\rm 6=3x+1\]
zepdrix
  • zepdrix
3. Get the `solution` by `applying Algebra`. I'm not really sure what she wants for this step, maybe something like that. You get the solution by applying steps.
zepdrix
  • zepdrix
4. `Verify` your solution. After you have found your x value, you want to plug that value back into the original expression and make sure that it holds true.
zepdrix
  • zepdrix
I think there is some popular expression that teachers use which is KISS = keep it simple, stupid I'm not sure where it comes from, but it sounds familiar :\
anonymous
  • anonymous
lol are in the usa
zepdrix
  • zepdrix
yes :U
anonymous
  • anonymous
ooh i thought you where not because its late lol
zepdrix
  • zepdrix
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.