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These types of equations?\[\large\rm 4x+3=2x-1\]
Do you remember the PEMDAS acronym? :) It tells you how to prioritize these different operations when trying to simplify something like this:\[\large\rm 5+6(2-1)\div2\]You prioritize brackets highest, doing the 2-1 first.\[\large\rm 5+6(1)\div2\]Then multiplying the 6 and 1,\[\large\rm 5+6(1)\div2\]Then division,\[\large\rm 5+3\]and finally adding,\[\large\rm 8\] You might wonder how that applies to algebraic equations involving one variable. Well, it turns out that `usually`, when you're trying to solve for some unknown, you would like to perform these steps in reverse. That is usually the most straight forward approach.
Lemme set up a more straight forward example actually,\[\large\rm 4x-3=9\]The idea is, in order to get x alone, solving for it, you need to "undo" a bunch of operations. So in this example, notice that the x is being `multiplied by 4` and `subtracted by 3`. We want to think of this PEMDAS idea but in reverse, we would like "undo" the most simple steps first. So to undo subtraction, we use addition. We'll start by adding 3 to each side of the equation. (By making the same change to each side, the equation stays true and balanced).\[\large\rm 4x-3+3=9+3\]The subtraction and addition undo one another on the left side of the equation,\[\large\rm 4x=9+3\]
I know I'm rambling on a bit here :) lol but it's a fun question
im confuse because the question
the question? :o
ya this is for my school work and i do not understand at all.the way she wrote the question
She gave you this question: `How can i solve linear equations in one variable?` and wants you to explain?
also KEEP IT ___________________. The goal is to figure out how much each x weight weighs. You do this by getting one x on one side and its value on the other side. STEPS TO SOLVING AN EQUATION 1. Simplify each side of the __________________. 2. Get the __________________ on one side of the ___________________. 3. Get the _____________ by ___________________. (Solve for the variable) 4. ___________ your solution. Follow along on page 3, Example 1. E2(x + 1) = 5x + 4 E x Simplify each side of the equation.
1. Simplify each side of the `equation`. Example: (Not using your example cause I'm not sure what the E's are about)\[\large\rm 2(x+3)=5x+1\]Simplifying the left side gives us,\[\large\rm 2x+6=5x+1\]
2. Get the `variable` on one side of the `equation`. We would like all of the x's on one side of the equation. It's usually better to move the smaller x's around. So in this example, I'll subtract 2x,\[\large\rm 6=5x+1-2x\]\[\large\rm 6=3x+1\]
3. Get the `solution` by `applying Algebra`. I'm not really sure what she wants for this step, maybe something like that. You get the solution by applying steps.
4. `Verify` your solution. After you have found your x value, you want to plug that value back into the original expression and make sure that it holds true.
I think there is some popular expression that teachers use which is KISS = keep it simple, stupid I'm not sure where it comes from, but it sounds familiar :\
lol are in the usa
ooh i thought you where not because its late lol