anonymous
  • anonymous
What is the discontinuity and zero of the function f(x) = 2x^2+5x-12 ----------- x+4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Answers: Discontinuity at (−4, −11), zero at ( three halves , 0) Discontinuity at (−4, −11), zero at ( negative three halves , 0) Discontinuity at (4, 5), zero at ( three halves , 0) Discontinuity at (4, 5), zero at ( negative three halves , 0
anonymous
  • anonymous
Please help, @Directrix
Directrix
  • Directrix
Factor this: 2x^2+5x-12 I am thinking that the denominator (x +4) will be a factor. If it is, we need to see the other factor.

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anonymous
  • anonymous
(2x-3)(x+4)
Directrix
  • Directrix
(2x-3)(x+4) ---------- (x + 4) Before dividing out the (x + 4) factors, take note that a point of discontinuity will occur when x = -4 because the denominator is 0 when x = -4.
anonymous
  • anonymous
Looking at my answers, I've got two that have -4, 11 as the discontinuity.
Directrix
  • Directrix
f(x) = (2x-3) where x is not -4 @DeadMovies Find f(-4) to get the y coordinate of the point of discontinuity f(-4) = (2*(-4) - 3) Multiply 2 times -4 and then subtract 3 from the product.
anonymous
  • anonymous
Okay, so my choices with those two numbers(-4, -11) as discontinuities are A, and B. Now we work on the zeros? @Directrix @mathmale
Directrix
  • Directrix
The zero is the x-intercept. f(x) = (2x-3) (2x-3)= 0 x = ?
Directrix
  • Directrix
@DeadMovies

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