Albert0898
  • Albert0898
WILL GIVE MEDAL! Please explain! 52. Given that (x+2) and (x-1) are factors of the quadratic expression below, what are the values of a and b? x^2 + (a+2)x + a + b a b F. -4 5 G. -3 1 H. -3 5 J. -1 3 K. -1 -1
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Albert0898
  • Albert0898
\[x^2 + (a+2)x + a + b\]
whpalmer4
  • whpalmer4
What do you get if you multiply \((x+2)(x-1)\)
Albert0898
  • Albert0898
\[x^2+x-2\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

whpalmer4
  • whpalmer4
Okay, so let's mix and match. \[x^2 + (a+2)x + a + b\]\[x^2 + x -2\] What do \(a,b\) have to be so that \((a+2)x = x\) and \(a+b = -2\)?
Albert0898
  • Albert0898
I haven't a clue...
whpalmer4
  • whpalmer4
Oh, come on. \[(a+2) x = x\]Solve that for \(a\)
Albert0898
  • Albert0898
ax + 2x = x ax = x - 2x a = 1 - 2
whpalmer4
  • whpalmer4
so \(a =\)
Albert0898
  • Albert0898
-1
whpalmer4
  • whpalmer4
right. now how about \(a+b =-2\) given that \(a = -1\)?
Albert0898
  • Albert0898
b = 1
Albert0898
  • Albert0898
OH NOW I GET IT!!!!
Albert0898
  • Albert0898
Because x^2 - sum x + product = 0
whpalmer4
  • whpalmer4
that's also a good way of looking at it, yes
Albert0898
  • Albert0898
One of those problems that you just have to write out and not do in your head... duh oh Thank you very much!
whpalmer4
  • whpalmer4
when you have factor a hairy polynomial, you can use that insight that the constant term is always a product of the constant terms of the factors to make educated guesses as to what might be a factor
whpalmer4
  • whpalmer4
Yeah, there are a lot of problems like this where you just write down one thing and write down another thing like it and say "what do I have to do to make these match?"
Albert0898
  • Albert0898
Understood, thanks again!
whpalmer4
  • whpalmer4
you bet! I always like watching the "oh, I see!" moments :-)

Looking for something else?

Not the answer you are looking for? Search for more explanations.