Koilds
  • Koilds
At 9:00 on Saturday morning, two bicyclists heading in opposite direction pass each other on a bicycle path. The bicyclist heading north is riding 4km/hour faster than the bicyclist heading south. At 10:15, they are 40 km apart. Find the two bicyclists' rates. A: Northbound bicyclist = 18 km/h; southbound bicyclist = 14 km/h B: northbound bicyclist = 19 km/h; southbound bicyclist = 15 km/h C: northbound bicyclist = 18 km/h; southbound bicyclist = 13 km/h D: northbound bicyclist = 16 km/h; southbound bicyclist = 10 km/h
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I found this online it might help: let v = the rate of the bicyclist heading south v + 4 = the rate of the bicyclist heading north (4 km/hour faster) d = 40 km the sum of the distances that each of the bicyclists passes t = 10:15 - 9:00 = 1 hr 15 min = 1.25 hr since the rate = distance/time follows distance = rate*time and we have v*t + (v + 4)*t = d v*1.25 + (v + 4)*1.25 = 40 by solving we find v = 14 km/hour click here to see the step by step solution of the equation http://doyourmath.com/redirect/174/3f55d74973c0ac77c742ad7033610d42?q=c%3Dsolve_algequationsolve%26v27%3Dv%2A1.25%2B%252B%2B%28v%2B%252B%2B4%29%2A1.25%2B%253D%2B40%26v28%3Dv v + 4 = 14 + 4 = 18 km/hour. The rate of the bicyclist heading south is 14 km/hour. The rate of the bicyclist heading north is 18 km/hour.
Koilds
  • Koilds
Thanks :)
anonymous
  • anonymous
Sure ;)

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TheSmartOne
  • TheSmartOne
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