ExceptionLearner
  • ExceptionLearner
Solve (x-2)4 (cube)=81
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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AaronAndyson
  • AaronAndyson
take a screenshot of the original question.I am having trouble intercept the problem :/
anonymous
  • anonymous
Can we assume that because you haven't answered that Directrix got it right? ^
ExceptionLearner
  • ExceptionLearner
Where's the draw tab?

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ExceptionLearner
  • ExceptionLearner
Yes he got is some what but there's no 3 and he forgot "=81" at the end
anonymous
  • anonymous
The draw tab will be under the text box that you are typing in,
ExceptionLearner
  • ExceptionLearner
Well I'm using a phone, I don't think they have draw tabs for it :(
anonymous
  • anonymous
Well, if there is no 3, then what does the cube mean.
ExceptionLearner
  • ExceptionLearner
Sorry I got it mixed with another problem. I mean 4 to the fourth power
ExceptionLearner
  • ExceptionLearner
(x-2)4 (four to the fourth power)= 81
anonymous
  • anonymous
Now we are getting somewhere.
mathmale
  • mathmale
(x-2)4 (cube)=81 should be handwritten (use the Draw utility, below) , or typed in as (x-2)^4 = 81. If you want to be fancy, use Equation Editor, below:\[(x-2)^4=81\]
mathmale
  • mathmale
If you take the fourth root of the left side of this equation, you will have isolated (x-2). You must also take the fourth root of 81, which, by the way, has more than one answer. Find all values of x for which \[(x-2)^4=81\]
mathmale
  • mathmale
is true.
ExceptionLearner
  • ExceptionLearner
@math make that's exactly what the problem looks like. I'm new to openstudy
ExceptionLearner
  • ExceptionLearner
@mathmale **
mathmale
  • mathmale
I'd be glad to help, but am unsure of what you're asking me for.
ExceptionLearner
  • ExceptionLearner
I need help solving the problem. That's all the problem ask Solve (x-2)^4=81
mathmale
  • mathmale
"Solving" an equation implies the need to isolate the unknown. In this case, that unknown is x. What's the value (or, what are the values) of x that satisfy the original equation?
mathmale
  • mathmale
Just as an example: let x=1 and test this to see whether it is indeed a solution of the given equation. Solve (x-2)4 (cube)=81 Let x=1, which leads to (1-2)^4=81. that's (-1)^4 = 81, or 1=81. Obviously not true, and so x=1 is not a solution.
mathmale
  • mathmale
As before, this equation should be displayed as \[(x-2)^4=81.\]
mathmale
  • mathmale
We need to isolate x-2, and then, in turn, to isolate x. Taking the 4th root of both sides of the equation:\[\sqrt[4]{(x-2)^4}=\pm \sqrt[4]{81}\]
mathmale
  • mathmale
the left side of the equation becomes simply x-2. The right side becomes\[\pm \sqrt[4]{3^4}, \]
mathmale
  • mathmale
since 3^4 = 81 = 3*3*3*3
mathmale
  • mathmale
so we end up with \[x-2=\pm2\]
mathmale
  • mathmale
Solve this for x. We end up with what? Note that because 81= 3^4, the maximum number of solutions could be 4. We're not finished until we've checked both x=3 and x=-3. Try it. Write the set that represents all of the solutions.
mathmale
  • mathmale
|dw:1449896834853:dw|
ExceptionLearner
  • ExceptionLearner
Thank you
ExceptionLearner
  • ExceptionLearner
x-2=3 x-2=-3 x € { 5, (-1) }

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