anonymous
  • anonymous
suppose certain coins have weights that are normally distributed with a mean of 5.767 g and a standard deviation of 0.076 g. A vending machine is configured to accept those coins with weights between 5.677 g. and 5.857 g a. If 290 different coins are inserted into the vending machine, what is the expected number of rejected coins? (round to the nearest integer)
Statistics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
mathmale
  • mathmale
Big picture: You'll first need to find the area under the normal cur e between 5.677 and 5.857 grams. Are you able to do that?
anonymous
  • anonymous
no
mathmale
  • mathmale
Have you used a table of z-scores before?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yes
mathmale
  • mathmale
Good. Find the z-score corresponding to 5.857 grams when the mean is 5.757 and the std. dev. is 0.076 grams
mathmale
  • mathmale
the proper formula to use is the following:|dw:1449937049116:dw|
mathmale
  • mathmale
To find the z-score for 5.857, let x = 5.857, the mean = 5.767 and the std. dev. 0.076. Evaluate z. Then do the same for the lower limit, 5.677. What are the two z scores?
mathmale
  • mathmale
Melissa: OpenStudy reports that you're "just looking around." Time for me to get off OpenStudy. If convenient for me, I 'll continue helping you when you and I have both returned.
anonymous
  • anonymous
I am still trying to figure out this Z score
anonymous
  • anonymous
I am slow. Not good with statistics.
anonymous
  • anonymous
Is the z score for 5.857 1.2?
anonymous
  • anonymous
then for the lower number the z score would be -1.2?
anonymous
  • anonymous
I am here

Looking for something else?

Not the answer you are looking for? Search for more explanations.