Alex_Mattucci
  • Alex_Mattucci
What are the exact solutions of x2 - x - 4 = 0? A. x= -1(+or-) Sqrt (15)/2 B. x= 1(+or-) Sqrt (15)/2 C. x= 1(+or-) Sqrt (17)/2 D. x= -1(+or-) Sqrt (17)/2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Alex_Mattucci
  • Alex_Mattucci
In another way...
Alex_Mattucci
  • Alex_Mattucci
|dw:1449939783808:dw|
Alex_Mattucci
  • Alex_Mattucci
@Michele_Laino or @pgpilot326

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More answers

Nerdsarecool
  • Nerdsarecool
Well
Nerdsarecool
  • Nerdsarecool
Right of the bat which ones can we eliminate
Alex_Mattucci
  • Alex_Mattucci
no clue
Nerdsarecool
  • Nerdsarecool
Oh ok
Nerdsarecool
  • Nerdsarecool
So
Nerdsarecool
  • Nerdsarecool
Look at the questions and tell me which ones don't makes sense
Alex_Mattucci
  • Alex_Mattucci
The ones with a positive 1. So B and C
Nerdsarecool
  • Nerdsarecool
Ok
Luigi0210
  • Luigi0210
You're gonna need to use the quadratic formula, do you know it?
Nerdsarecool
  • Nerdsarecool
I know
Alex_Mattucci
  • Alex_Mattucci
not really, no
Nerdsarecool
  • Nerdsarecool
I am trying to calculate it
Luigi0210
  • Luigi0210
Well, try walking them through it, don't just give them the answer (:
Nerdsarecool
  • Nerdsarecool
I am not
Nerdsarecool
  • Nerdsarecool
Ok
Nerdsarecool
  • Nerdsarecool
Tell me about A
Nerdsarecool
  • Nerdsarecool
What is the answer to a
Nerdsarecool
  • Nerdsarecool
Look at it and tell me when you are done
Alex_Mattucci
  • Alex_Mattucci
A is one of the answers
Nerdsarecool
  • Nerdsarecool
Because if you look at all of the questions and look at which one makes sense then you will get it
♪Chibiterasu
  • ♪Chibiterasu
\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]
Nerdsarecool
  • Nerdsarecool
Don't tell him the answer
♪Chibiterasu
  • ♪Chibiterasu
That's the quadartic formula . . .
Nerdsarecool
  • Nerdsarecool
Oh
Nerdsarecool
  • Nerdsarecool
I am in algebra 1 so
Nerdsarecool
  • Nerdsarecool
This is to hard for me
Nerdsarecool
  • Nerdsarecool
Pooja
Nerdsarecool
  • Nerdsarecool
Hello
Nerdsarecool
  • Nerdsarecool
He needs some help
pooja195
  • pooja195
How about you start off by listing the ABC values @Alex_Mattucci
pooja195
  • pooja195
a=? b=? c=?
Nerdsarecool
  • Nerdsarecool
I don't need help
♪Chibiterasu
  • ♪Chibiterasu
I think she was referring to alex . . .
Alex_Mattucci
  • Alex_Mattucci
ok, a=1;b=-1;c=-4
♪Chibiterasu
  • ♪Chibiterasu
Good, so now you can plug those in.
pooja195
  • pooja195
Good now plug them into the quadratic formula \[\huge~\rm~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
♪Chibiterasu
  • ♪Chibiterasu
Solve and that will be your answer.
Michele_Laino
  • Michele_Laino
here we have to apply the standard formula: \[x = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\] where \(a=1,\;b=-1,\;c=-4\)
pooja195
  • pooja195
Here i think it'll be hard for you to copy the formula idk if you know latex or not... \[\huge~\rm~x=\frac{ -(-1) \pm \sqrt{(-1)^2-4(1)(-4)} }{ 2(1) }\]
Alex_Mattucci
  • Alex_Mattucci
i got this |dw:1449940724316:dw|
♪Chibiterasu
  • ♪Chibiterasu
It's not 1 - 4 since they are being multipled, it's 1 * -4
pooja195
  • pooja195
\[\huge~\rm~x=\frac{ 1 \pm \sqrt{(-1)^2-4(1)(-4)} }{ 2(1) }\] use this.
Alex_Mattucci
  • Alex_Mattucci
ok
Nerdsarecool
  • Nerdsarecool
Pooja
Nerdsarecool
  • Nerdsarecool
How do you wright so perfect
pooja195
  • pooja195
Solve whats in the square root first DO NOT square root it though
Nerdsarecool
  • Nerdsarecool
All of the lines are straight
pooja195
  • pooja195
It's LaTex i'll teach you after =] lets keep the comment relevant to the question please!
Alex_Mattucci
  • Alex_Mattucci
I GOT IT! |dw:1449941040073:dw|
Alex_Mattucci
  • Alex_Mattucci
@ pooja
♪Chibiterasu
  • ♪Chibiterasu
Good job :)
Nerdsarecool
  • Nerdsarecool
Guys
♪Chibiterasu
  • ♪Chibiterasu
hmm hold on
Nerdsarecool
  • Nerdsarecool
How do you earn the points
Nerdsarecool
  • Nerdsarecool
Smartscore Points
♪Chibiterasu
  • ♪Chibiterasu
-1^2 = 1 -4(1)-4) 16 + 1 = 17 nvm you're right, good job =)
pooja195
  • pooja195
Well done.
♪Chibiterasu
  • ♪Chibiterasu
@Nerdsarecool Every little thing you do on OpenStudy can increase your smartscore. It's how well you do these things to increase it. There's no fast easy way to increase it. It takes time. For the problem solving portion, you must answer questions not only in detail, but guiding the user to understanding the problem. Giving direct answers is not only not allowed, but it doesn't even help the user understand anything. Plus, direct answers don't increase your smartscore as fast as answering in detail would. Teamwork! One thing people consider to be somewhat hard to do. By gaining fans as well as fanning users, you are then increasing your smartscore even more! The more fans you earn, the higher you go. But be aware that creating accounts to fan yourself doesn't increase your smartscore by much. Also, it's not allowed and could lead to your main account being suspended forever. You best bet would be to enter chats, as well as help out a lot. Lastly we have engagement. Here is the fun part, when you ask questions you're increasing your smartscore! Isn't that cool? You can increase your smartscore just by making threads you need help on! Not to mention the amount of medals you earn and give out can help increase it faster! But keep in mind, spamming yourself with medals isn't allowed on here and will not increase your smartscore fast at all. Another thing about engagement is that the longer you're on here, the higher your smartscore goes too! It's as if almost everything on here will increase your smartscore. It can be fun and I hope you find it very fun too. I hope you have the best time on OpenStudy and good luck with the journey on here. c: ~beccaboo333
Alex_Mattucci
  • Alex_Mattucci
Could i trouble you guys for another question?
♪Chibiterasu
  • ♪Chibiterasu
Sure, go ahead and close this one and open a new one.
Alex_Mattucci
  • Alex_Mattucci
ok

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