Christos
  • Christos
physics, who's gonna help me do part (c) from here ? https://www.dropbox.com/s/k0h82hlyamrouub/Screenshot%202015-12-12%2019.01.26.png?dl=0
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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hartnn
  • hartnn
a = dv/dt so acceleration at t = 5 is the slope of tangent at t=5 just find the slope at t=5
Christos
  • Christos
can you tell me why are you allowed here to use a = dv/dt
hartnn
  • hartnn
a = dv/dt can be used everywhere.. .why not here

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Christos
  • Christos
I heard somewhere that you have to have something to be 'constant'
Christos
  • Christos
for instance there are also other equations that we could use
hartnn
  • hartnn
quite vague... calculating derivative d/dt is equivalent to finding the slope of tangent to the curve
Christos
  • Christos
like https://www.dropbox.com/s/por0m84c684teur/Screenshot%202015-12-12%2019.12.42.png?dl=0
Christos
  • Christos
could we use one of those ?
hartnn
  • hartnn
sure finding slope will be equivalent to using \(v_x = v_{0x} + a_x t\)
Christos
  • Christos
if we differantiate that we get a
hartnn
  • hartnn
\(a_x = \dfrac{v_x - v_{0t}}{t}\)
Christos
  • Christos
dv/dt of v+at => just a
hartnn
  • hartnn
yeah but how would u use that to find a
Christos
  • Christos
aaah I see
Christos
  • Christos
One last question, do you think that there is a way to find part (a) using integral and not area ?
Christos
  • Christos
have always been using area, but I wanna know integral way as well
hartnn
  • hartnn
integration is equivalent to finding the area under the curve. when you have the equation, you use integration. when you have the graph, you use area
Christos
  • Christos
you mean kinematic equation ? Or I need a specific function of v(t) given by exersise ?
hartnn
  • hartnn
specific function for v like in this case, v will have 3 parts, linear from 0 to 2, constant from 2 to 4 linear from 4 to 6 and then you'd need to integrate each part separately
Christos
  • Christos
oohh I see. Thanks a lot for the help!

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