Alex_Mattucci
  • Alex_Mattucci
What are the approximate solutions of 2x^2 + x = 14 rounded to the nearest hundredth? a. x ≈ -2.41 and x ≈ 2.91 b. x ≈ -2.91 and x ≈ 2.41 c. x ≈ -5.82 and x ≈ 4.82 d. No real solutions
Mathematics
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SOLVED
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chestercat
  • chestercat
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welshfella
  • welshfella
2x^2 +x - 14 = 0 to solve use the quadratic formula x = [-b +/- sqrt(b^2-4ac)] / 2a where the equatuion is of the form ax^2 + bx + c = 0
welshfella
  • welshfella
so here a = 2, b = 1 and c = -14 plug these values into the formula
welshfella
  • welshfella
the +/- means there are 2 values for x as follows |dw:1449941747625:dw|

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welshfella
  • welshfella
and the other has a '-' after the -b
welshfella
  • welshfella
|dw:1449941882537:dw|
welshfella
  • welshfella
just plug in b = 1 , a = 2 and c = -14 and calculate
Alex_Mattucci
  • Alex_Mattucci
sorry, i am back, my dad needed me real quick
welshfella
  • welshfella
ok you see where the a,b and c come from ? they are the numbers in the equation 2x^2 + x - 14 = 0
welshfella
  • welshfella
x = 1x
Alex_Mattucci
  • Alex_Mattucci
yes
Alex_Mattucci
  • Alex_Mattucci
i found that the answer is B
Alex_Mattucci
  • Alex_Mattucci
x ≈ -2.91 and x ≈ 2.41
Alex_Mattucci
  • Alex_Mattucci
Thank you for your help!!!
welshfella
  • welshfella
welcome
welshfella
  • welshfella
B is correct

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