anonymous
  • anonymous
help on solving x^2n-2x^n-3 Most of the time people say you can't solve it but my math book says the answer is (x^n-3)(x^n+1). I understand how to factor it but... what happened to the x^2n? The 2? Because once you put it in this form after you x-factor: (x^2n-3x^n+1x^n-3) and you group them (x^2n-3x^n)+(1x^n-3) When you take the common factor out to simplify you get: X^n(x^2-3)+1(x^n-3) ....am i doing something wrong?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
x^(2n) = (x^n)^2
amistre64
  • amistre64
id solve for u^2 -2u -3, given that u=x^n
mathmale
  • mathmale
x^2n-2x^n-3 is ambiguous, and should be written with parentheses as amistre64 has show you here. It never hurts to use parentheses, whereas leaving out necessary parentheses can lead to great confusion.

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More answers

mathmale
  • mathmale
u^2 -2u -3 is a quadratic expression. Which methods of factoring quadratics do you know? Apply one here.
anonymous
  • anonymous
i know the -b+-Radical(b)^2-4ac / 2a
amistre64
  • amistre64
x^n (x^2-3) x^n x^2 is not equal to x^(2n) x^n x^2 =x^(2+n)
amistre64
  • amistre64
x^n x^n = x^(n+n) = x^(2n)
anonymous
  • anonymous
oh i see
anonymous
  • anonymous
so how do i take it out of that final step after you group them?
anonymous
  • anonymous
i just take one x^n out?
amistre64
  • amistre64
factor it correctly :)
anonymous
  • anonymous
oh oh!!!!! so if i take only one x^2n out i get X^n left still!
anonymous
  • anonymous
SHHHHHH THANK YOU
amistre64
  • amistre64
yep
amistre64
  • amistre64
(x^n x^n-3x^n)+(x^n-3) x^n (x^n-3)+(x^n-3) etc...

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