anonymous
  • anonymous
Fidn a quadratic equation with roots -1+4i and -1-4i
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Find*
anonymous
  • anonymous
(x - root)(x - root), so you need to mulitply \[(x + 1 - 4i)(x+1+4i)\] When you do the imaginary parts will cancel and you'll have the quadratic
anonymous
  • anonymous
@peachpi is right

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anonymous
  • anonymous
I still don't understand it very well... i'm sorry @peachpi
anonymous
  • anonymous
do you know how to foil?
anonymous
  • anonymous
No not very well @peachpi
anonymous
  • anonymous
that's ok. basically it's just applying the distributive property. You take each term from the 1st parentheses and multiply it by each term in the second. Starting with the \(x\) in the 1st, multiply and get \(x(x+1+4i)=x^2+x+4ix\) You try it with the 2nd and third terms. Just distribute. 2nd: \(1(x+1+4i)=\) 3rd: \(-4i(x+1+4i)=\)
anonymous
  • anonymous
2nd: x+1+4i 3rd: -4ix-4i-16i right? @peachpi
anonymous
  • anonymous
The second one is right. The third is almost right. -16i should be -16i². Then because \(i^2=-1\), it reduces to 16. Altogether is should be \(-4ix-4i+16\) Make sense?
anonymous
  • anonymous
Yep makes sense now! @peachpi
anonymous
  • anonymous
so now all you have to do is add up what we got from the multiplication for each step. Every term with an i will cancel, and then combine everything else to get the final answer
anonymous
  • anonymous
Okay thanks so much @peachpi

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