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ABCD is a rhombus is 1
I already got that one, I probably should have put that. It's the reasons I need help on.
I'm not sure if this is correct but I think 6 is Definition of Perpendicular Lines/Angles
The first reason is "given." Since there is only one given in the statement of the problem, the first statement must be 1. ABCD is a rhombus
The second statement states that all sides of the rhombus have equal lengths. We know all sides of a rhombus have equal lengths because that is the definition of rhombus. Reason 2. Definition of rhombus
BTW, there is a mistake in statement 2. It mentions lengths AD and DA, but they are the same. Statement 2 should be: AB = BC = CD = DA
We have this so far. |dw:1450025630495:dw|
Now we state statement 3, and we have this: |dw:1450025742231:dw|
Statement 4 is incorrect. It is proving the wrong pair of triangles, and we don't have enough info for it yet anyway.
Statement 4 should be: 4. AO = AO 4. Reflexive property of equality. Now we have this: |dw:1450025883748:dw|
Now we prove the correct pair of triangles congruent: 5. Triangle ADO is congruent to triangle ABO 5. SSS 6. <1 is congruent to <2 6. CPCTC 7. <1 and <2 are right angles 7. If 2 angles are congruent and supplementary, then they are right angles. 8. Line AC is perpendicular to line DB 8. Definition of perpendicular lines