pooja195
  • pooja195
Balancing equations
Chemistry
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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pooja195
  • pooja195
\[\bf~\rm~CaCl_2+Al_2(C_2O_4)_3\rightarrow CaC_2O_4+AlCl_3\]
bubblegum.
  • bubblegum.
:) 1st did you try doing this?
pooja195
  • pooja195
No because i am hopelessly lost and i have no idea how to do this

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bubblegum.
  • bubblegum.
oh okay :) when we balance a chemical equation we just see that total number of atoms of 1 element are same on both sides of the equation now the question is how do we find out total number of atoms of an element in one compound. so to do this just follow these steps->|dw:1450035545688:dw| now 1st your work is to get this point^
pooja195
  • pooja195
im confused :/
bubblegum.
  • bubblegum.
okay do you know why a reaction is called unbalanced or balanced
pooja195
  • pooja195
nope ._.
bubblegum.
  • bubblegum.
okay \(\bf~\rm~CaCl_2+Al_2(C_2O_4)_3\rightarrow CaC_2O_4+AlCl_3\) in this equation can you find number of atoms of \(Ca~and~Cl\) in 1 molecule of \(CaCl_2\) which is on the left
pooja195
  • pooja195
Ca 1 Cl 2 ?
bubblegum.
  • bubblegum.
yea correct! and now can you count the number of atoms of \(Ca~and~Cl\) on the right side
pooja195
  • pooja195
Ca 1 C1 3
bubblegum.
  • bubblegum.
yes correct :) now compare the number of atoms of these 2 elements on the right and left do u think there is something wrong it in :)
pooja195
  • pooja195
Yes
pooja195
  • pooja195
C1 2 <---right side Cl 3 <---left side
bubblegum.
  • bubblegum.
yes :D this is reason why the reaction is unbalanced! and we are gonna balance it by multiplying the terms with suitable numbers for example- \(\color{red}{2}H_2+O_2=2H_2O\)
pooja195
  • pooja195
I see hmm alright ok soo Can't we multiply the 3 by 2 and 2 by 3 ?
bubblegum.
  • bubblegum.
\(\bf~\rm~\color{red}{3}CaCl_2+Al_2(C_2O_4)_3\rightarrow CaC_2O_4+\color{red}{2}AlCl_3\) if you do this then the \(Ca\) atoms change on left but the \(Al\) atoms gets balanced now you gotta make evrything/every element balanced
pooja195
  • pooja195
See this is the part thats confusing >.<
bubblegum.
  • bubblegum.
ok so till now what can you say :) which all elements are balanced? you are close to the correct answer tho :D
pooja195
  • pooja195
\[\bf~\rm~2CaCl_2+1Al_2(C_2O_4)_3\rightarrow 2CaC_2O_4+1AlCl_3\]
bubblegum.
  • bubblegum.
no no this is wrong the \(Cl,~Al,~C\) atoms are unbalanced
pooja195
  • pooja195
;-;
bubblegum.
  • bubblegum.
\(\bf~\rm~\color{red}{3}CaCl_2+Al_2(C_2O_4)_3\rightarrow CaC_2O_4+\color{red}{2}AlCl_3\) we had this^ now look at it carefully e_e we see that we have balanced \(Cl,~Al\) and now we have 3 atoms of \(Ca\) on left but only 1 on right 6 atoms of \(C\) on left but only 3 on right 12atoms of \(O\) on left but only 4 on right now think to multiply something to \(CaC_2O_4\) :)
pooja195
  • pooja195
4 ;~;?
bubblegum.
  • bubblegum.
how did you get 4?
pooja195
  • pooja195
Wait would i distribute the 3?
bubblegum.
  • bubblegum.
sorry that will be-> 6 atoms of \(C\) on left and 2 on the right yeah 3 is that number :) just see if this fixes it all :) \(\color{red}{3}CaC_2O_4\)
pooja195
  • pooja195
;-; this is so confusing
bubblegum.
  • bubblegum.
do you agree that \(Cl~and~Al\) are balanced?
pooja195
  • pooja195
Yes
bubblegum.
  • bubblegum.
okay so so far we have this-\(\bf~\rm~\color{red}{3}CaCl_2+Al_2(C_2O_4)_3\rightarrow CaC_2O_4+\color{red}{2}AlCl_3\) Now do you agree that -> 3 atoms of Ca on left but only 1 on right 6 atoms of C on left but only 2 on right 12atoms of O on left but only 4 on right
pooja195
  • pooja195
Yes
bubblegum.
  • bubblegum.
3 atoms of Ca on left but only 1 on right 6 atoms of C on left but only 2 on right 12atoms of O on left but only 4 on right so what shall you multiply on the right^ to get what is on the left :)
pooja195
  • pooja195
1) 3 on the right 2) 3 on the right 3) 3 on the right
bubblegum.
  • bubblegum.
yeah! :D so we gotta multiply the right with a 3 and if we do this then \(C,~O~and~Ca\) get balanced and \(Al~and~Cl\) are already balanced so can you rewrite the final equation now
pooja195
  • pooja195
\[\bf~\rm~3CaCl_2+3Al_2(C_2O_4)_3\rightarrow 3CaC_2O_4+3AlCl_3\]
bubblegum.
  • bubblegum.
jst a sec ima reload :)
pooja195
  • pooja195
o.O
pooja195
  • pooja195
buble gum come back T_T
bubblegum.
  • bubblegum.
m here typing :)
bubblegum.
  • bubblegum.
:) you don't have to multiply the whole equation you only have to mutiply the part that you wanna fix try to find out if what u did was correct or not by calculating if the number of atoms are balanced you did till here->\(\bf~\rm~\color{red}{3}CaCl_2+Al_2(C_2O_4)_3\rightarrow CaC_2O_4+\color{red}{2}AlCl_3\) and then u see that the unbalanced elements \(C,~O,~Ca\) on the left are thrice of that on the right so you have to multiply by 3 on the right \(\bf~\rm~\color{red}{3}CaCl_2+Al_2(C_2O_4)_3\rightarrow \color{blue}{3}CaC_2O_4+\color{red}{2}AlCl_3\)
pooja195
  • pooja195
OH ok makes a bit more sense THANK YOU SO MUCH <#3333
bubblegum.
  • bubblegum.
hhaaha np (;
pooja195
  • pooja195
;)

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