At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
So if the graph is y = x^7, what would you go to get a y value?
I'm not sure that's how it is. Math is really confusing to me. All this has is that its undefined and its x=7. Doesn't undefined mean it has no y?
Ah, understood. Ill go step by step. So if you want to find two points on a graph, you need X and Y coordinates. Have you seen (x,y)? That would be a point on the graph. But before I do this, did the problem say x=7 or x7 as in x to the power of 7? Like was the 7 a little number above the x?
it says x=7
Alright, so if y=7 is a HORIZONTAL line at the point y = 7, then x = 7 would be a VERTICAL line at the point x = 7. Does that make sense so far?
So lets take a graph. Would you be able to find the X value of positive 7?
wouldn't it be (0,7)?
Almost Remember the coordinate is (x,y)
oh, so (7,0)
Correct Also known as x=7, see that?
Because the x in (x,y) is 7
I do. so how would I get a second point? Would it be (14,0) to be following the pattern?
If you want the second point to stay on the line x = 7, you can't change the x For your example, (14,0), you changed the x. Now it reads that x = 14 The only thing you can change is the y
what would a second point be in that case?
You give me a guess. Remember those two things I said You can't change the x You can change the y It's a line also, so lines never stop, which means you have an infinity amount of choices
so it would need to be up or down on 7x, right? it could be a positive or negative?
Right, the y value can be any number you wish
That makes sense. so for y=3, the y would stay the same but the x could be anything horizontal from that?
Correct! So let's do y = 3 Since that means (x,y) is (x,3), the x can be any number, like literally You can put (4,3) or (-3,3) or (6,000,000,000,000,000, 3), as long as the y value remains at 3
i get that part now. thank you! I have a huge project for my algebra class and my teacher isn't much help. would you be able to help me with graphing it as well?
oh, crap, i have to go do something. do you have a kik account or anything?
I don't, but I'm on here, like alot. We could meet sometime later on here
I should be back later today to finish, so that should work. Thanks a ton