j3nny0rtiz
  • j3nny0rtiz
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth. A. 51.9, 52, 49, 6 B. 52.9, 52, 49, 104 C. 51.9, 53, 49, 6 D. 52, 52.9, 49, 104
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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j3nny0rtiz
  • j3nny0rtiz
pls help I will give medal.
jchick
  • jchick
Do you know how to do this?
jchick
  • jchick
The mean, median, mode, and range of this data are: A. 51.9, 52, 49, 6

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More answers

jchick
  • jchick
The mean is the average of the numbers: a calculated "central" value of a set of numbers. To calculate: Just add up all the numbers, then divide by how many numbers there are.
jchick
  • jchick
To find the Median, place the numbers you are given in value order and find the middle number.
jchick
  • jchick
The mode of a set of numbers is the one that occurs most often. So, in the set {1,5,7,5,9}, the mode is 5 because there are 2 fives and only one of each of the others.
j3nny0rtiz
  • j3nny0rtiz
oh I get it now thanks
jchick
  • jchick
No problem
jchick
  • jchick
Any more?
j3nny0rtiz
  • j3nny0rtiz
I have a lot more lol..
jchick
  • jchick
Ok tag me in them.
jchick
  • jchick
By the way what class is this?
j3nny0rtiz
  • j3nny0rtiz
|dw:1450041584972:dw|
jchick
  • jchick
Oh this one is simple. Do you know your order of operations?
jchick
  • jchick
Otherwise known as PEMDAS
jchick
  • jchick
Simplify the expression using the rules of exponents.
jchick
  • jchick
Actually never mind about the order of operations. All you need to do is take the exponent of three and multiply by 5.
jchick
  • jchick
Which comes up with an answer of x^15
j3nny0rtiz
  • j3nny0rtiz
thank you so much
jchick
  • jchick
No problem!
j3nny0rtiz
  • j3nny0rtiz
Find the GCF. 18x 3 and 30x 5 A. 6x 5 B. 90x 3 C. 6x 3 D. 90x 5
jchick
  • jchick
\(x^3 = x \times x \times x\) \(x^5 = x \times x \times x \times x \times x\)You can factor out an x^3 since it is in both. THerefore, it is: \(GCF = 6x^3\)
jchick
  • jchick
Find the prime factors of each term in order to find the greatest common factor (GCF).

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