anonymous
  • anonymous
After a devastating winter, when thousands of fish died, an environmental scientist has replenished the trout stock in a fishing pond. He started with 8,000 baby trout and has finished a count to find that, in 5 years, the population is estimated to be 24,000. Assuming an exponential growth pattern, what is the annual growth rate (rounded to the nearest tenth of a percent) of the new trout population? Hint: A(t) = A0(1+r)^t, where A(t) is the final amount, A0 is the initial amount, r is the growth rate expressed as a decimal, and t is time. A. 33.3% B. 2.5% C. 60.0% D. 24.6%
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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xapproachesinfinity
  • xapproachesinfinity
you just need to solve for r in that equation \[A(t)=A_0 (1+r)^t\] in five years we have \[A(5)=8000(1+r)^5\] \[24000=8000(1+r)^5 \]
xapproachesinfinity
  • xapproachesinfinity
can you solve for r?
anonymous
  • anonymous
I think so

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anonymous
  • anonymous
\[r = -1 + \sqrt[5]{3}\]
anonymous
  • anonymous
@xapproachesinfinity Is that right?
xapproachesinfinity
  • xapproachesinfinity
so what is the value?
anonymous
  • anonymous
I'm not 100% sure. Could you maybe walk me through this? I don't really understand. If you have time at least
xapproachesinfinity
  • xapproachesinfinity
you already did half the work just use calculator
anonymous
  • anonymous
Ok one sec
anonymous
  • anonymous
I got 0.2457
xapproachesinfinity
  • xapproachesinfinity
you need to multiply by 100
anonymous
  • anonymous
So 24.57
xapproachesinfinity
  • xapproachesinfinity
so?
anonymous
  • anonymous
So the last choice?
xapproachesinfinity
  • xapproachesinfinity
yes
anonymous
  • anonymous
Thank you for your help

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