None of your answers
How do I figure it out?
One square has the side of 8, and the other has a side of 2 To find the area of the total figure, you add up the areas of both squares
I had also posted that on your previous post ^
So is it 10 or 20?
I feel so freaking dumb...
What is the area of a square with a side length of 8?
If a square has a side lenght of x, then the area is x^2 \(\sf x^2 = x\cdot x\)
Doesn't help me at all, you're confusing me more than I already am...
Well, lets see if @robtobey can explain it better :)
Sorry. Had to correct a couple of items. The area of a the square, 8 ft by 10ft-2ft, 8 ft, on each side is 64 ft^2. 64+2ft*2ft is 68 ft^2 in total.
Robtobey is correct, and also you are correct about your second problem.
Find the distance between points P(8,2) and Q(3,8) to the nearest tenth. I got D=36.3. Is this right?
The second problem. The mathematical solution to 8 x + 8 = 7 x + 4 is x = -4
Where do you get 4?
It's 8x-8 = 7x+8
The picture states: 8x + 8 = 7x + 8 Therefore, 8x = 7x and x = 0
Yep, I got an F on this one.
Sorry I made a mistake on the first drawing.