Jashley
  • Jashley
equation of the line containing given point and perpendicular to given point (6,7) y=-5x+7
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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mathstudent55
  • mathstudent55
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mathstudent55
  • mathstudent55
The slope of the given line is -5. The slopes of perpendicular lines are negative reciprocals. That means that if you know the slope of a line, and you want the slope of the other line, flip the fraction, and change the sign. -5 as a fraction is \(-\dfrac{5}{1} \) Flip that fraction and change the sign. What do you get for the slope of the perpendicular line?
Jashley
  • Jashley
is it y=-5x-23

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Jashley
  • Jashley
well -5/1-23
mathstudent55
  • mathstudent55
What do you get for the slope of the perpendicular?
Jashley
  • Jashley
5/1
Jashley
  • Jashley
1/5
mathstudent55
  • mathstudent55
Correct. You flipped the fraction, and changed the sign, so the slope of the perpendicular is 1/5.
mathstudent55
  • mathstudent55
\(y = mx + b\) \(y = \dfrac{1}{5} x + b\) We are given a point. We replace x and y with the coordinates of the point, and we find b. \(7 = \dfrac{1}{5}(6) + b\) \(35 = 6 + 5b\) \(29 = 5b\) \(b = \dfrac{29}{5} \) The equation of the perpendicular line is: \( y = \dfrac{1}{5}x + \dfrac{29}{5} \)
Jashley
  • Jashley
thank you this method is alot easier
Jashley
  • Jashley
what about (6,-4) 9x+2y=7

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