EmogirlAtEmoooocow
  • EmogirlAtEmoooocow
Ralphie's dad has a nutritionist who instructed him to consume less than 2,121 calories per day. He has already eaten 1,585 calories today and wants to eat some fruit bars that are 62 calories each. Which of the following inequalities could be used to solve for x, the number of fruit bars Ralphie's dad can eat without going over his calorie allotment? A. 62x – 1,585 < 2,121 B. 62x + 1,585 < 2,121 C. 62x < 2,121 D. 62x < 1,585
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
a
EmogirlAtEmoooocow
  • EmogirlAtEmoooocow
explain pls.
anonymous
  • anonymous
Well he needs to eat at most 2121 calories so everything has to be less than 2121. He's already eaten 1585 calories the fruit bars are 62 calories each so thats why its 62x, the x value is how many fruit bars he eats hence why 62x-1585<2121

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

EmogirlAtEmoooocow
  • EmogirlAtEmoooocow
im still confuses
mathmate
  • mathmate
|dw:1450102738382:dw| Let x= max. number of portions that he can eat without busting the target So 1585+62x <2121
mathmate
  • mathmate
* should read 62 Cal.each in diagram
mathstudent55
  • mathstudent55
\(\sf \color{red}{calories ~already ~eaten} ~plus ~\color{green}{calories ~to ~be ~eaten} ~must ~be ~less ~than ~\color{purple}{2121}\) \(\sf \color{red}{(calories ~already ~eaten)} ~+ ~\color{green}{(calories ~to ~be ~eaten)} ~< ~\color{purple}{2121}\) The calories to be eaten are 62 for each bar. x bars have 62x calories \(\sf \color{red}{1585} ~+ ~\color{green}{62x} ~< ~\color{purple}{2121}\) Now we use the commutative property to rewrite as: \(\sf ~\color{green}{62x}~+~\color{red}{1585} ~< ~\color{purple}{2121}\)
EmogirlAtEmoooocow
  • EmogirlAtEmoooocow
so b @mathstudent55
mathmate
  • mathmate
|dw:1450106988651:dw| Note: when dealing with diets and food, we are working with Calories, or kilocalories (kcal). "calorie" is a unit too small to be practical for food energy measurements.

Looking for something else?

Not the answer you are looking for? Search for more explanations.