GabeBae
  • GabeBae
geometry help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
GabeBae
  • GabeBae
@dr0zier99
1 Attachment
F_Jayyy
  • F_Jayyy
wouldnt it be 40?
GabeBae
  • GabeBae
explain?

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More answers

mathstudent55
  • mathstudent55
You have two different 30-60-90 triangles. Find AC and BC using the triangles. The answer is AC - BC
dr0zier99
  • dr0zier99
i think that the answer is b AC: \(\normalsize\tan(60) = \frac{AC}{10 \sqrt{3}} \implies \sqrt{3} = \frac{AC}{10 \sqrt{3}}\) \(\normalsize\ AC = 10 \sqrt{3} \times \sqrt{3} = 30\) BC: \(\normalsize\ tan(30) = \frac{BC}{10 \sqrt{3}} \implies \frac{1}{\sqrt{3}} = \frac{BC}{10 \sqrt{3}} \implies BC = 10\) \(\ AB = 30 - 10 = 20\)
dr0zier99
  • dr0zier99
is that write
mathstudent55
  • mathstudent55
|dw:1450106047582:dw|
GabeBae
  • GabeBae
wow.. i'm so confused right now
dr0zier99
  • dr0zier99
i say that the answer is b
mathstudent55
  • mathstudent55
In a 30-60-90 triangle, the long leg is \(\sqrt 3\) times longer than the short leg.
GabeBae
  • GabeBae
so 20 feet?
dr0zier99
  • dr0zier99
i would think so
anonymous
  • anonymous
me also
mathstudent55
  • mathstudent55
|dw:1450106148499:dw|
GabeBae
  • GabeBae
another question please?
anonymous
  • anonymous
sure
GabeBae
  • GabeBae
1 Attachment
mathstudent55
  • mathstudent55
|dw:1450106202547:dw|
anonymous
  • anonymous
I would have to say that it is answer choice A because thast is the one that makes the most sense.
mathstudent55
  • mathstudent55
AC - BC = AB = 30 - 10 = 20
dr0zier99
  • dr0zier99
si
GabeBae
  • GabeBae
wait which question are we on?
mathstudent55
  • mathstudent55
There is a reason why each post in OS should be for only one question.
GabeBae
  • GabeBae
:/
anonymous
  • anonymous
wait, what grade level is this? I am only in 9th grade.
mathstudent55
  • mathstudent55
|dw:1450106423517:dw|
mathstudent55
  • mathstudent55
|dw:1450106526333:dw|
mathstudent55
  • mathstudent55
|dw:1450106559308:dw|
anonymous
  • anonymous
what grade level is this?
mathstudent55
  • mathstudent55
|dw:1450106634873:dw|
mathstudent55
  • mathstudent55
Now that you know adj, opp, and hyp, you can find sin x. \(\sin x = \dfrac{opp}{hyp} \)
GabeBae
  • GabeBae
I'm in 9th too this is part of my geometry honors course
anonymous
  • anonymous
okay, then. I havent gotten to this part yet. Sorry I cant help you.

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