Bookworm14
  • Bookworm14
I am not 100% sure I got these right could you check please? thank you!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Bookworm14
  • Bookworm14
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anonymous
  • anonymous
they all look okay to me. I dont know if they are right or not.
Bookworm14
  • Bookworm14
they were all greater than zero in the discriminant so I thought that would mean 2 solutions, but all of the answer choices have me confused and second guessing

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Bookworm14
  • Bookworm14
what do yall think?
whpalmer4
  • whpalmer4
They are not all correct. How did you determine your answer choices?
Bookworm14
  • Bookworm14
I put them into quadratic formula form and then solved the discriminant. In each case they were all greater than zero, meaning two solutions (I thought)
whpalmer4
  • whpalmer4
Well, yes, it does mean that, but it doesn't tell you that all of the solutions will be positive ones. For example, how about \[x^2+2x-3=0\] What is discriminant?
whpalmer4
  • whpalmer4
and what are solutions?
Bookworm14
  • Bookworm14
the discriminant is sqrt 4-4(1)(-3)= sqrt 16 = 4?
whpalmer4
  • whpalmer4
no, no square root, or the discriminant would always be positive. discriminant for a quadratic is just \(b^2 - 4ac\)
Bookworm14
  • Bookworm14
so it would be 16 then?
whpalmer4
  • whpalmer4
so discriminant for this equation is 16. But what are the solutions? Hint: \[x^2+2x-3 = (x-1)(x+3)\]
Bookworm14
  • Bookworm14
1, -3 ? wait is this wanting me to factor not do the discriminant?
Bookworm14
  • Bookworm14
cuz im awesome at factoring! lol
whpalmer4
  • whpalmer4
No, I'm trying to enlighten you about the meaning of various values of the discriminant. So here we have a quadratic with a positive discriminant, but not all of the solutions are positive. That means that we cannot assume that a positive discriminant --> all solutions positive.
Bookworm14
  • Bookworm14
oh ok, I see what you are saying! I cant just assume that because the discriminant came out to be positive, that all solution for the equation are positive
whpalmer4
  • whpalmer4
What we can determine from the discriminant is this: \[\Delta = b^2 - 4ac\]\[\Delta > 0 \rightarrow \text{2 real solutions}\]\[\Delta = 0\rightarrow \text{1 real solution with multiplicity 2}\]\[\Delta < 0 \rightarrow\text{2 complex solutions in conjugate form, }a\pm bi\]
whpalmer4
  • whpalmer4
multiplicity 2 means that there's a solution that happens twice. For example: \[y = x^2\]has \[\Delta = 0^2-4(1)(0) = 0\]and the solutions are obviously \[x=0,x=0\]
Bookworm14
  • Bookworm14
? new answers i got?
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whpalmer4
  • whpalmer4
So to do this problem, you can use the discriminant to make the first classification (real solutions, single real solution, complex solutions) but you'll need to factor or otherwise solve to do the second part of characterizing those solutions.
whpalmer4
  • whpalmer4
Your answer for #38 is still incorrect. @Bookworm14
anonymous
  • anonymous
Do you still need help?
Bookworm14
  • Bookworm14
idk where i went wrong
whpalmer4
  • whpalmer4
What do you get for solutions for problem 38?

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