iwanttogotostanford
  • iwanttogotostanford
PL
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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SolomonZelman
  • SolomonZelman
Well, as far as the domain goes, this is a polynomial so your domain should be blurred out (correctly) right away.
SolomonZelman
  • SolomonZelman
Is \(\large\color{#000000 }{ \displaystyle f(x) }\) (in our case) ever undefined, for any \(x\) ??
iwanttogotostanford
  • iwanttogotostanford
@SolomonZelman no

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SolomonZelman
  • SolomonZelman
Yes, right f(x), in this case, is defined for any value of x. Therefore, what can you conclude about the domain of this function?
iwanttogotostanford
  • iwanttogotostanford
@SolomonZelman the vertex is -2, 4?
YoloShroom
  • YoloShroom
yup, y=a(x-h)^2+k h,k is the vertex. In this case, h and K are -2,4
SolomonZelman
  • SolomonZelman
(2,4) is the vertex, actually, but nice try though...
iwanttogotostanford
  • iwanttogotostanford
IM CONFUSED: The vertex is (2, 4), the domain is all real numbers, and the range is y ≤ 4. The vertex is (2, 4), the domain is all real numbers, and the range is y ≥ 4. WHICH ONE WOULD IT BE? @SolomonZelman
SolomonZelman
  • SolomonZelman
When the parabola opens up the vertex is the minimum point, and when opens down the vertex is the maximum point. parabola in a form \(\large\color{#000000 }{ \displaystyle y(x)=a(x-h)^2+k }\) opens down if \(a<0\). opens up if \(a>0\).
iwanttogotostanford
  • iwanttogotostanford
so it would be the first one!
SolomonZelman
  • SolomonZelman
(1) Does your parabola open down or up? (2) Is the vertex (2,4) the minimum or maximum of your parabola? (3) Does that mean that y (the range) is at least 4 (4 or greater), or does that mean that y (the range) is at most 4 (4 or less)?
SolomonZelman
  • SolomonZelman
(1) Opens Up
SolomonZelman
  • SolomonZelman
And from there it should be obvious.
iwanttogotostanford
  • iwanttogotostanford
oh ok second one, thanks! @SolomonZelman
iwanttogotostanford
  • iwanttogotostanford
@SolomonZelman correct?
iwanttogotostanford
  • iwanttogotostanford
@SolomonZelman
anonymous
  • anonymous
should be ionlywantanswers
anonymous
  • anonymous
not the path to stanford...

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