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If 2x2 + y2 = −2 then evaluate the second derivative of y with respect to x when x = 2 and y = 3.
I'll fan or medal or whatever, just stuck on this one question.
Do I find the second derivative, then plug in the values. Do I plug them in after differentiating once then differentiate again?
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Did you find the first derivative?
It's implicit derivative, so I'd find the derivative of both sides seperately, yeah? That'd be 2 y y'(x)+4 x = 0?
Am I wrong? Can someone help further?
2x2 + y2 = −2
4x + 2yy' = 0
Agreed. Now, the second derivative. You need only one things you didn't use before, the product rule. What are you going to do with 2yy'?
You can solve for y', first. Sometimes that helps. Sometimes, that just makes it worse.
wait I think that was the wrong problem
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