Hayhayz
  • Hayhayz
http://prntscr.com/9e75p4 @dan815
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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dan815
  • dan815
x^2-5x+6 can you factor this
dan815
  • dan815
okay sure
dan815
  • dan815
|dw:1450127432216:dw|

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dan815
  • dan815
now we want the constant multiplcation to be 6
dan815
  • dan815
then u see the different ways to multiply to see so that when u expand the brackets out u also get -5x
dan815
  • dan815
|dw:1450127540190:dw|
dan815
  • dan815
and these 2 constants make it work
dan815
  • dan815
-2*-3=6 there are ways to multiply to 6 but they wont end up giving u -5x if u expand like 6*1=6 3*2=6 -6*-1=6 -2*-3=6<--- this is the only one that works to give u -5x when u do (x-2)(x-3) = x^2-5x+6
dan815
  • dan815
can you try to factor 2x^2-7x+3 ill start for you since u know 2x^2 exists lets try starting with 2x*x=2x^2 (2x )(x ) not that also -2x *-x = 2x^2 but we started with the other one
dan815
  • dan815
note*

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