Melissa_Something
  • Melissa_Something
Balancing equations :(
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Melissa_Something
  • Melissa_Something
\[C_9 H _{20} + O_2 ----> CO_2 +H_2 O\]
Melissa_Something
  • Melissa_Something
I got the answer, just don't know why my teacher put a 14 in front of O
aaronq
  • aaronq
what do you have so far?

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Melissa_Something
  • Melissa_Something
C_9 H_20 + 26O_2 ----> 9Co_2 + 10H_2O
Melissa_Something
  • Melissa_Something
@aaronq But instead of the 26 in front of the O my teacher put 14
aaronq
  • aaronq
so on the right side of the equation, you have 9*2+10=28 oxygens on the left side you have \(O_2\) the subscript works like distributive property in math. \(2*(2x)=4x\) same thing in chem \(14~O_2=28~O\)
aaronq
  • aaronq
Let me know if that doesn't make sense to you
Melissa_Something
  • Melissa_Something
Im trying to study sorry, it kinda doesnt make sense
Melissa_Something
  • Melissa_Something
Where is the 10 on the right side you speak of? @aaronq
aaronq
  • aaronq
\(\sf \large C_9 H_{20} + 14~O_2 ----> 9~CO_2 + \underbrace{10}_{here}~H_2O\)
Melissa_Something
  • Melissa_Something
Okay I got it! Do you mind explaining the subscript thing again? It would always multiply?
aaronq
  • aaronq
yes, always multiply. Also when a number is not explicitly written as a subscript a 1 is assumed, like in math when you have \(x\), it means \(x^1\). so for example, you have \(H_2SO_4\) if you have a coefficient (number in front) of 3 \(3*(H_2SO_4)\) then you have 3*2=6 H 3*1=3 S 3*4=12 O it gets a little more complex when you have subscripts in brackets, for example: \(Fe(H_2O)_2Cl\) you have 1 Fe, 4 H's, 2 O'2 and 1 Cl
Melissa_Something
  • Melissa_Something
Thank you so much :) !!!!!!
aaronq
  • aaronq
no problem (:

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