anonymous
  • anonymous
Write the complete balanced equation for the reaction between barium metal (Ba) and nitrogen gas (N2). You do not need to make the subscripts smaller; just write them out as regular numbers. Will someone help me with this? I think that its just BaN2 but some places are saying its not
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@chemENGINEER
aaronq
  • aaronq
That's a strange reaction, but we can think about this logically, Barium metal (elemental) has 2 loosely held electrons (in the 6s orbital) easily it can lose (and in turn be oxidized). Nitrogen (being more electronegative) can obtain these electrons and be reduced.. question is how many? Each N in \(N_2\) has 5 electrons, to complete it's octet it will gain 3. \(Ba\rightarrow Ba^{2+}+2e\) \(N_2+6e^-\rightarrow 2N^{3-} \) --------------------------------- \(3Ba\rightarrow 3Ba^{2+}+6e\) \(N_2+6e^-\rightarrow 2N^{3-} \) --------------------------------- \(3Ba+ 2N_2 +\cancel{6e^-}\rightarrow Ba_3N_2+\cancel{6e^-}\) the only way to get this formula to work (because of the electrons exchanged) is having the product be \(Ba_3N_2\).
anonymous
  • anonymous
Oh wow thank you so much!!!!

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aaronq
  • aaronq
no problem! next time just use the charges the elements obtain (when they gain or lose electrons to achieve a noble gas configuration (i.e. an octet)) to predict the compounds formed.

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