Sen_Turtle
  • Sen_Turtle
A 4.0kg brick is sitting on a table. The coefficient of static friction between the surfaces is 0.45. If a 10 N horizontal force is applied to the brick, what will be the force of friction? pls send help 2 a fellow Norwegian in need
Physics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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denisaboichuk
  • denisaboichuk
half
anonymous
  • anonymous
Using Newton's 2nd Law, we have:\[\huge \sum \text{F}=\sum_i^nm_ia_i\]This can be reduced to:\[\huge \text{F}_\text{applied}-\text{F}_\text{frictional}=0\]Note that this equation is equal to 0. This is because the problem notes that the object is "sitting" and not moving with a constant acceleration. We already have the applied force, but we do not know the frictional force. In any case, we can define the frictional force as:\[\huge \text{F}_\text{frictional}=\mu \text{N}\] Now our full equation becomes\[\huge \text{F}_\text{applied}-\mu \text{N}=0\]next what you need to do is find what the normal force is. You can either easily do it by inspection, or if you're not fully advanced with the material yet, draw another free body diagram and analyze the forces in the y direction. It's a simple one. After you have figured out what N is and you plugged it in, just solve for \(\mu\).

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anonymous
  • anonymous
@denisaboichuk ??

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