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one sec I'ma graph it
the triangle at the bottom, is that your answer?
No that was there.
dang I'm so confused, could I help with another?
yeah one second.
Okay so there are some on here where its like you answer in a. b. and c. so when you answer can you clarify which is which? @MysticalFlames
Okay I'll try that
Thanks so much!
I just replied to your message on google btw.
I got #1! Oh okay I can't use hangouts rn but I'll reply when I can :D
okay thanks so much.
Okay so: To find the area of the hexagon, we need to divide the picture into a triangle Find the area of each triangle Finally add the area of triangles to get the area of the hexagon.
Is that what I put?
wait one sec there's a little more
To find the area of the hexagon, we need to divide the picture into a triangle Find the area of the triangle (Base*height/2). Finally add the area of triangles to get the area of the hexagon. <-- just put that
You're so smart, thanks so much bby.
Tell me when you get the others.
Okay I'm solving rn
Okay I got #2!
In 3 dimensions, think of a cube with one corner on the origin (0,0,0) and the opposite corner on (7,7,7). The distance = square root (49 + 49 + 49) = square root (147) = 12.124 cm
Okay that looks complicated let me simplify, here's what you write:
In 3 dimensions, a cube with one corner on the origin (0,0,0) and the opposite corner on (7,7,7). The distance = square root (49 + 49 + 49) = square root (147) = 12.124 cm
So thats what ill put for number 2?
but how would i separate it for a and b
I don't think you need to
So that answer should be okay?
Yeah, I hope.
Thanks so much! I think number 3 is all thats left. If theres anything I can help you with, I'd love to.
oh btw: for #1 you could also write this: If we write down the formula for finding the area of a hexagon with a given apothem, write down the apothem. Use the apothem to find the perimeter. Plug all of the known quantities into the formula, and simplify.
Thanks! I'll let you know if there's anything :) So #3 is all? There's nothing else?
I think thats it, ill look after and let you know. Im so pissed my microsoft word just failed so bad.
Okay, hey I gtg for a while but this is what I have for now: the slope of the line (PG) = -4/3 the slope of the line (MR) = -4/3 then since both slopes are equivalent , we deduce that (PG) and (MR) are parallel , thus (PM) and (GR) are parallel as well, then PGRM is a parallelogram.
When will you be able to get back on?
Is there anyway to communicate?
for 5a, change (a,b) to (-a,-b) to get the image
e.g R is (3,2) so image is (-3,-2)
5b, change (a,b) to (-a,b)
5c, do what the question says
Im so confused.
5 a? I don't think i have 5a.
The first question you posted says 5 on the top, and have sub questions a b and c
Oh tanks ill look over it tomorrow.!
do you need help on the otters questions you posted below
I will maybe later but I think he gave me the correct answers, ill let you know tomorrow, goodnight!