anonymous
  • anonymous
WILL FAN AND MEDAL Line l is represented by the equation 2x+y=9 What it the Slope of a line parallel to line l? What is the slope of the line perpendicular to line l?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
first find the slope of \[2x+y=9\] by solving for \(y\) (in one step)
anonymous
  • anonymous
the slope of the parallel line will be the same the slope of the perpendicular line will be the "negative reciprocal" i.e. flip it and change the sign
anonymous
  • anonymous
did you get that or no?

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anonymous
  • anonymous
not really, sorry
anonymous
  • anonymous
you have \[2x+y=9\] and you want the slope the slope of \[y=\color{red}mx+b\] is \(\color{red}m\) so you want to write the equation to look like that so you can see the slope with your eyeballs that is why i said "solve for x"
anonymous
  • anonymous
i mean "solve for y"
anonymous
  • anonymous
\[2x+y=9\] subtract \(2x\) from both sides, what do you get?
anonymous
  • anonymous
you get y = 9 -2x
anonymous
  • anonymous
right, or \[y=\color{red}{-2}x+9\] making the slope ???
anonymous
  • anonymous
negative ?
anonymous
  • anonymous
lol yes it is negative for sure more specifically it is \(-2\)
anonymous
  • anonymous
got that? it is the number in front of the x
anonymous
  • anonymous
yeah I got that
anonymous
  • anonymous
ok then the parallel line has the same slope
anonymous
  • anonymous
and the perpendicular is -1/2x?
anonymous
  • anonymous
no
anonymous
  • anonymous
the slope of the perpendicular line is what you are asked for, a number, no variable it is the "negative reciprocal" you flipped it, but did not change the sign
anonymous
  • anonymous
i.e. the slope with be the number \(\frac{1}{2}\) the minus sign goes
anonymous
  • anonymous
1/-2?
anonymous
  • anonymous
\[-\frac{1}{2}=\frac{-1}{2}=\frac{1}{-2}\] but the negative reciprocal of \(-2\) is just \[\frac{1}{2}\] with no minus sign
anonymous
  • anonymous
thank you. Mind I tag you in 1 more?
anonymous
  • anonymous
no not at all
anonymous
  • anonymous
or you can post it here if you like

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