How do i solve this trig equation? tan(3Θ)+1=0 where 0<=Θ<2π

How do i solve this trig equation? tan(3Θ)+1=0 where 0<=Θ<2π

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can you divide the 3 out of the tanΘ?

would you have to change the restriction to \[0\le3\theta <6\Pi\]

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