How do i solve this trig equation? tan(3Θ)+1=0 where 0<=Θ<2π
Stacey Warren - Expert brainly.com
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can you divide the 3 out of the tanΘ?
There are several ways, but I think one of the easier to follow is to replace 3 theta temporarily with x and solve the resulting equation: tan x + 1
would you have to change the restriction to \[0\le3\theta <6\Pi\]
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that is, tan x + 1 + 0. for what angle or angles, between 0 and 2pi, is tan x = -1?
the reference angle for 1 is pi/4, and tan is negative is quadrants 2 and 4 so it is 3pi/4 and 7pi/8?
would you have to change the restriction to
0≤3θ<6Π ? Let's solve the problem; after which I'd bet you could answer your own question.
tan 3Pi/4 is indeed equal to -1. I'm not convinced that 7Pi/8 is a solution; have you checked it in tan x + 1 = 0?
ohh i meant 7pi/4
so then you set that equal to tan(3Θ) and divide by 3
You probably remember that the period of the tangent function is pi (not 2pi as with the sine and cosine).
Almost. Set 3pi/4 equal to 3 theta and solve for theta.
Then do the same for 7pi/8. checking your own answer (value(s) of theta) will tell you whether you're right that 7pi/4 is a solution of tan x + 1 = 0.