anonymous
  • anonymous
How do i solve this trig equation? tan(3Θ)+1=0 where 0<=Θ<2π
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
can you divide the 3 out of the tanΘ?
mathmale
  • mathmale
There are several ways, but I think one of the easier to follow is to replace 3 theta temporarily with x and solve the resulting equation: tan x + 1
anonymous
  • anonymous
would you have to change the restriction to \[0\le3\theta <6\Pi\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

mathmale
  • mathmale
that is, tan x + 1 + 0. for what angle or angles, between 0 and 2pi, is tan x = -1?
anonymous
  • anonymous
the reference angle for 1 is pi/4, and tan is negative is quadrants 2 and 4 so it is 3pi/4 and 7pi/8?
mathmale
  • mathmale
would you have to change the restriction to 0≤3θ<6Π ? Let's solve the problem; after which I'd bet you could answer your own question.
mathmale
  • mathmale
tan 3Pi/4 is indeed equal to -1. I'm not convinced that 7Pi/8 is a solution; have you checked it in tan x + 1 = 0?
anonymous
  • anonymous
ohh i meant 7pi/4
anonymous
  • anonymous
so then you set that equal to tan(3Θ) and divide by 3
mathmale
  • mathmale
You probably remember that the period of the tangent function is pi (not 2pi as with the sine and cosine). Almost. Set 3pi/4 equal to 3 theta and solve for theta. Then do the same for 7pi/8. checking your own answer (value(s) of theta) will tell you whether you're right that 7pi/4 is a solution of tan x + 1 = 0.
anonymous
  • anonymous
ok, thanks!
mathmale
  • mathmale
My pleasure. Shall i assume we're done?
anonymous
  • anonymous
yes!
mathmale
  • mathmale
Good for you. Hope to work with you again.

Looking for something else?

Not the answer you are looking for? Search for more explanations.