rainbow_rocks03
  • rainbow_rocks03
Plz help me!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
rainbow_rocks03
  • rainbow_rocks03
An astronaut who weighed 765 newtons on Earth found that his weight on Jupiter was 1800 newtons. While visiting Jupiter, he captured an alien that weighed 1200 newtons on Jupiter. What will be the alien's weight on Earth? A. 443 newtons B. 510 newtons C. 742 newtons D. 985 newtons
YumYum247
  • YumYum247
To help you i gotta go through my notes......
rainbow_rocks03
  • rainbow_rocks03
alright. :)

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More answers

YumYum247
  • YumYum247
will you fan me if i help you?!?!?!?
YumYum247
  • YumYum247
LOL
rainbow_rocks03
  • rainbow_rocks03
sure. :D
anonymous
  • anonymous
I was helping you. I already solved it and was about to go through it. Oh well! Not my problem :)
rainbow_rocks03
  • rainbow_rocks03
Oh, well you didnt have to be kind of rude about it, or at least you sounded rude
rainbow_rocks03
  • rainbow_rocks03
@YumYum247 I will fan you if you help me with this question, + I will medal you if you help me with another question! :D
YumYum247
  • YumYum247
gimme a sec...
rainbow_rocks03
  • rainbow_rocks03
alright.
anonymous
  • anonymous
No I was not being rude, I was being up front that you remarks weren't significant to solving the problem :)
rainbow_rocks03
  • rainbow_rocks03
oh. :)
YumYum247
  • YumYum247
are you two done so i can begin?!?!?!?
rainbow_rocks03
  • rainbow_rocks03
I have been waiting on you
rainbow_rocks03
  • rainbow_rocks03
you didnt have to be rude about it. :(
YumYum247
  • YumYum247
ok your question is based on newton's third law of motion which states that every action has a reaction force acting with the same magnitude but in the opposite direction...so when you stand on earth...your weight is exerting a certain force against the earth and the earth is exerting the same force back at you....
rainbow_rocks03
  • rainbow_rocks03
ok.
YumYum247
  • YumYum247
you need to use the following formula.....F = 6.67 X 10^-11N.m^2 (m1)(m2)/Kg^2/d^2
YumYum247
  • YumYum247
let me write it dow for you.....hehehe
YumYum247
  • YumYum247
|dw:1450156710126:dw|
YumYum247
  • YumYum247
oh shayyy....i just realized you have three variables already given to you.... you can use them to find the fourth missing one!!! LOL i think it's 510 N
anonymous
  • anonymous
You're not using the right equation.
YumYum247
  • YumYum247
if it's a math questionnn do the following....|dw:1450157102536:dw|
anonymous
  • anonymous
Yes that is one way to do it. The other equation you included is the gravitational force between any two masses.
anonymous
  • anonymous
It is irrelevant here.
anonymous
  • anonymous
The other way to do it would be using F=mg a bunch of times. I get the same answer as well of 510N. X)
anonymous
  • anonymous
It appears that he has left anyway.
YumYum247
  • YumYum247
he'll be back :)
denisaboichuk
  • denisaboichuk
Answer is b

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