anonymous
  • anonymous
find the area of triangle of its two side measure 6 in and 9 in and the bisector angle between sides id 4 square root of 3
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Find the area of a triangle if its two sides measure 6in.6in. and 9in.9in., and the bisector of the angle between the sides is 43√43 in. I'm thinking of using the formula AA=12bh12bh I can't find the base or height, I used the Angle bisector formula which is l=l=ab[(a+b)2−c2]√a+bab[(a+b)2−c2]a+b So i found out C which i think is the base should i multiply it by 22? because I think it's the half. From here I'm lost geometry
anonymous
  • anonymous
Find the area of a triangle if its two sides measure 6in.6in. and 9in.9in., and the bisector of the angle between the sides is 43√43 in. I'm thinking of using the formula AA=12bh12bh I can't find the base or height, I used the Angle bisector formula which is l=l=ab[(a+b)2−c2]√a+bab[(a+b)2−c2]a+b So i found out C which i think is the base should i multiply it by 22? because I think it's the half. From here I'm lost geometry

Looking for something else?

Not the answer you are looking for? Search for more explanations.