steve816
  • steve816
I just took a math test, but there was a rigged question. Do not worry everyone, I'm not cheating, I already took the test and asking the question after taking it. It is about trigonometry and I was getting headache attempting the problem.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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steve816
  • steve816
\[\tan(3x) + 1 = \sec(3x) \]
steve816
  • steve816
Find all solutions.
zepdrix
  • zepdrix
Rigged? :) lol

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More answers

steve816
  • steve816
I knew that I had to substitute the 3x with just a single x, but I just couldn't solve from there.
zepdrix
  • zepdrix
Here is my approach, square both sides,\[\large\rm \tan^2(3x)+2\tan(3x)+1=\sec^2(3x)\]Use your Pythagorean Identity on the right side of the equation,\[\large\rm \tan^2(3x)+2\tan(3x)+1=\tan^2(3x)+1\]And then you have a lot of nice cancellations from there :) Any confusion?
steve816
  • steve816
Wait, where did you get the 2tan(3x) And now that you say pythagorean identity, I feel so dumb that I didn't recognize it :(
steve816
  • steve816
I'm a failure at math! Nooooooo, my test score is ruined :(
zepdrix
  • zepdrix
\[\large\rm (a+1)^2=a^2+\color{orangered}{2a}+1^2\]
zepdrix
  • zepdrix
\[\large\rm (\tan3x+1)^2=\tan^2(3x)+\color{orangered}{2\tan3x}+1^2\]
UnkleRhaukus
  • UnkleRhaukus
tan + 1 = sec sin/cos + cos/cos = 1/cos sin + cos = 1 (cos ≠ 0)
steve816
  • steve816
ohhhh, I understand now.
zepdrix
  • zepdrix
ya sines and cosines is another good approach :)
steve816
  • steve816
Alright, thanks guys.

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