For how many natural numbers \(n\) the expression\[\dfrac{1^3+2^3+...+n^3}{1^2+2^2+...+n^2}\]becomes a natural number?

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\[\left(\frac{n(n+1)}{2}\right)^2\]and\[\frac{n(n+1)(2n+1)}{6}\]

\[= \frac{3n(n+1)}{2(2n+1)}\]

oh boy messed up that calculation

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