anonymous
  • anonymous
A hyena can run one over four of a mile in 22.5 seconds. At this rate, which equation can be used to determine how fast a hyena runs in miles per hour? one-fourth mile over twenty-two point five seconds = 40 miles per hour twenty-two point five seconds over one-fourth mile = 40 miles per hour one-fourth mile over twenty-two point five seconds = 90 miles per hour twenty-two point five seconds over one-fourth mile = 90 miles per hour
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@Landon34 can you help
anonymous
  • anonymous
@annie12m
anonymous
  • anonymous
@Howard-Wolowitz

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anonymous
  • anonymous
Are you at least between either 90 or 40?
anonymous
  • anonymous
??? @OrangeMaster
anonymous
  • anonymous
Have you even narrowed the choices?
anonymous
  • anonymous
yeah, i thought it was D or C @OrangeMaster
anonymous
  • anonymous
@OrangeMaster Please help
anonymous
  • anonymous
@SM17E If you still want help on this, I can help.
anonymous
  • anonymous
Yes!! @LegendarySadist
anonymous
  • anonymous
Well there are two parts to the question. The concept and the implementation. The concept is pretty simple. The beginning asks you whether you should put the 22.5 over the .25 or vice versa. Since what you are trying to find is the speed, it would be \[\large \sf Speed=\frac{distance}{Time}\] I'll leave it to you to figure which one is the distance and which one is the time. The implementation is a bit more complicated. You want to stay with the formula \[\large \sf S=\frac{d}{t}\] (The same formula as the one up there) but since you are in seconds you have to convert the seconds to hours.
anonymous
  • anonymous
Hmm, im still a little confused
anonymous
  • anonymous
Basically find out how many times 22.5 seconds goes into an hour (aka 3600 seconds) and then multiply d/t by that.
anonymous
  • anonymous
oooh ok thank you! @LegendarySadist
anonymous
  • anonymous
ye no problem, tell me if you have any other questions :)
anonymous
  • anonymous
ok!! i will thank you!

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