anonymous
  • anonymous
In the diagram, segment CD is tangent to the circle, AB = 6 in, and BD = 10 in. Find AD.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
http://media.edgenuity.com/evresources/2072532_4f97338f-9357-40e0-a4c7-89dfcf96ea12.png
anonymous
  • anonymous
I keep getting 16.73
TrojanPoem
  • TrojanPoem
|dw:1450214490603:dw| Cos theta = 6/10 = 3/5 (first triangle) Costheta = [ (10)^2 + (6)^2 - x^2 ]/2 * 10 * 6 = 136 - x^2/120 (2nd triangle) costheta = 3/5 = (-136-x^2)/120 136 - x^2 = 72 x^2 = 64 x = 8 in #

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anonymous
  • anonymous
your answer is 2root61
anonymous
  • anonymous
i think
anonymous
  • anonymous
@TrojanPoem Thank you c:
TrojanPoem
  • TrojanPoem
Any time.
radar
  • radar
The segment AD or "x" is the hypotenuse of a right triangle ADC. Use Pythagorean theorem or \[x ^{2}=\sqrt{12^{2}+8^{2}}=\sqrt{208}=4\sqrt{13}=14.42\]
TrojanPoem
  • TrojanPoem
@radar , correct I forgot a sign. Cos theta = 6/10 = 3/5 (first triangle) Cos(180 - theta) = (This was missing =>) - costheta = [ (10)^2 + (6)^2 - x^2 ]/2 * 10 * 6 = 136 - x^2/120 (2nd triangle) costheta = -3/5 = (-136-x^2)/120 136 - x^2 = -72 x^2 = 208 x = 4 sqrt(13) = 14.42 in

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